Answer:
The other angle is 120°.
Explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
...(I)
The range for the other angle is
....(II)
Here, distance and speed are same
On comparing both range
![\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bv%5E2%5Csin%282%5Ctheta%29%7D%7Bg%7D%3D%5Cdfrac%7Bv%5E2%5Csin%282%28%5Calpha-%5Ctheta%29%29%7D%7Bg%7D)
![\sin(2\theta)=\sin(2\times(\alpha-\theta))](https://tex.z-dn.net/?f=%5Csin%282%5Ctheta%29%3D%5Csin%282%5Ctimes%28%5Calpha-%5Ctheta%29%29)
![\sin120=\sin2(\alpha-60)](https://tex.z-dn.net/?f=%5Csin120%3D%5Csin2%28%5Calpha-60%29)
![120=2\alpha-120](https://tex.z-dn.net/?f=120%3D2%5Calpha-120)
![\alpha=\dfrac{120+120}{2}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B120%2B120%7D%7B2%7D)
![\alpha=120^{\circ}](https://tex.z-dn.net/?f=%5Calpha%3D120%5E%7B%5Ccirc%7D)
Hence, The other angle is 120°
Answer:
55.96kJ
Explanation:
Energy = mass of diethyl ether × enthalpy of vaporization of diethyl ether
Volume (v) = 200mL, density (d) = 0.7138g/mL
Mass = d × v = 0.7138 × 200 = 142.76g
Enthalpy of vaporization of diethyl ether = 29kJ/mol
MW of diethyl ether (C2H5)2O = 74g/mol
Enthalpy in kJ/g = 29kJ/mol ÷ 74g/mol = 0.392kJ/g
Energy = 142.76g × 0.392kJ/g = 55.96kJ
Answer:
A
Explanation:
The officer would have had permission regardless of anything else, kind of like letting someone into your house.
Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion
![v^{2}=u^{2}+2as](https://tex.z-dn.net/?f=v%5E%7B2%7D%3Du%5E%7B2%7D%2B2as)
![0^{2}=35^{2}- 2 \times 9.8 \times h](https://tex.z-dn.net/?f=0%5E%7B2%7D%3D35%5E%7B2%7D-%202%20%5Ctimes%209.8%20%5Ctimes%20h)
h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.