Answer: E. None of the above
Explanation: The energy of a photon is given by the formula below.
E=hf or E = hc/λ
E = energy, h = planck constant, c= speed of light and
λ= wavelength.
From E=hf we can see that energy is directly proportional to frequency since h is a constant, this implies that as we move up the visible light spectrum, red light has the least frequency this accounting for the lowest energy while violet has the largest energy accounting for a very high energy.
Blue light is higher in the spectrum than red light.
This implies that blue light has more energy than red.
Visible light is part of the electromagnetic spectrum which implies that they all travel with the same speed of a constant value ( speed of light = 3* 10^8 m/s).
Thus in conclusion, blue light has more energy that red light but they both travel with the same speed.
This point nullifies the options thus making none of it correct.
I can't imagine that this is going to do you much good, but
I'm sure going to enjoy solving it.
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Skip this whole first section.
It was an attempt to master a bunch of trees, while
the forest was right there in front of me all the time.
Drop down below the double line.
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Kepler's 3rd law says:
(square of the orbital period) / (cube of the orbital radius) = constant
T₀² = K R₀³
I put the zero subscripts in there, because you doubled 'R'
and I need to know how that affected 'T'.
new-T² = K(2 R₀)³
new-T² = 8 K (R₀)³ = 8 old-T₀²
<u> new-T = √8 old-T</u> <=== that's what I was after
I just teased out the Moon's new orbital period if it's distance were doubled.
Instead of 1 month, it's now √8 months.
To put a somewhat sharper point on it, the moon's period of revolution
changes from 27.322 days to 27.322√8 = 77.278 days (rounded) .
Using 385,000 km for the moon's current average distance, the current orbital speed is
(2π x 385,000 km) / (27.322 days) = 1,024.7 m/s
(One online source says 1.023 km, so we're not doing too badly so far.)
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I'm such a dummy. I don't need to go through all of that.
If the moon were twice as far from Earth as it really is, then it would
average 770,000 km instead of the present 385,000 km.
That's 120.86 times the Earth's radius of 6,371 km.
So the acceleration of gravity out there would be
(1 / 120.86)² of the (9.807 m/s²) that it is here on the surface.
new-G = 0.000671 m/s²
Distance a dropped object falls = 1/2 g t²
In the first second, that's 1/2 g (1)² = 1/2 g
For an orbiting object, every second is the "first"second, because ...
as we often explain orbital motion qualitatively ... the Earth "falls away"
just as fast as the curved orbit falls.
Distance an object falls in the 1st second =
1/2 G = 0.000336 m/s = <em>0.336 millimeter per second</em>
I estimate the probability of a mistake somewhere during this process
at approx 99.99% . But I don't have anything better right now, and I've
wasted too much time on it already, so I'll stick with it.
Answer:
260 km
65 km/hr
Explanation:
The displacement of an object is the distance moved by that object in a particular direction.
velocity = displacement / time, therefore,
Displacement = velocity * time.
Total displacement for the 4 HR trip = displacement for 2.5 hr + displacement for 1.5 hr
total displacement = (80 * 2.5) + (40 * 1.5)
Total displacement = 200 + 60
Total displacement = 260 Km
average velocity for the total trip = total displacement / total time taken
average velocity = 260 km/ 4 hr
average velocity = 65 km/hr
