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klio [65]
3 years ago
15

A car is traveling on a straight, level road under wintry conditions. Seeing a patch of ice ahead of her, the driver of the car

slams on her brakes and skids on dry pavement for 50 m , decelerating at 7.5 m/s2 . Then she hits the icy patch and skids another 70 m before coming to rest.
A) If her initial speed was 78 mi/h , what was the magnitude of the deceleration on the ice?
Physics
1 answer:
dangina [55]3 years ago
5 0
Her magnitude of deceleration on the ice would be 15.126m/s
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A 20,000 kg truck is traveling at 10 m/s. Calculate the truck's momentum. (p = m v)
kow [346]

Answer:

200,000 and 20,000,000

Explanation:

Substituting the values into the equation of momentum, we get that the momentum is p = mv = 20,000*10 = 200,000. Using the equation provided to solve for the force the truck experienced, we find: 20,000*10/0.01 = 20,000,000.

I hope this helps!

8 0
3 years ago
an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
Andrei [34K]

amount of work done is 5880 J

Given:

mass of object = 50kg

Final height = 20m

initial height = 8m

To Find:

amount of work done

Solution:

work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

The work done by gravity is given by the formula,

W = mgh

W = 50 x 9.8 x ( 20-8)

= 5880 J

So the work done is 5880 J

Learn more about Work done here:

brainly.com/question/25239010

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7 0
2 years ago
A helicopter starting on the ground is rising directly into the air at a rate of 25 ft/s. You are running on the ground starting
rusak2 [61]

Answer:

The rate of change of the distance between the helicopter and yourself (in ft/s) after 5 s is \sqrt{725} ft/ sec

Explanation:

Given:

h(t) =  25 ft/sec

x(t) = 10 ft/ sec

h(5) = 25 ft/sec . 5 = 125 ft

x(5) = 10 ft/sec . 5 = 50 ft

Now we can calculate the distance between the person and the helicopter by using the Pythagorean theorem

D(t) = \sqrt{h^2 + x^2}

Lets find the derivative of distance with respect to time

\frac{dD}{dt} (t)  = \frac{2h \cdot \frac{dh}{dt} +2x \cdot\frac{dx}{dt}} {2\sqrt{h^2 + x^2}}

Substituting the values of h(t) and  x(t) and simplifying we get,

\frac{dD}{dt}(t) = \frac{50t \cdot \frac{dh}{dt} + 20 \cdot \frac{dx}dt}{2\sqrt{625\cdot t^2 + 100 \cdot t^2}}

\frac{dh}{dt} = 25ft/sec

\frac{dx}{dt} = 10 ft/sec

\frac{Dd}{dt} (t) = \frac{1250t +200t}{2\sqrt{725}t}  = \frac{725}{\sqrt{725}}  = \sqrt{725} ft / sec

5 0
3 years ago
According to the Big Bang Theory, how long ago did the universe expand explosively into existence
Dmitry_Shevchenko [17]

About 13.7 billion years ago

The Big Bang Theory states that the universe started about 13.7 billion years ago, and before that, everything was in 1 singularity.



3 0
3 years ago
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lcompute the increase in length of 500 m of copper wire when it's temperature changes from 12 degrees celsius to 32 degrees Cels
marshall27 [118]

Explanation:

step by step explanation

7 0
3 years ago
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