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cricket20 [7]
3 years ago
14

You must give a signal either by hand and arm or by a signal device: Only if other traffic is affected by your movement Only at

night Anytime you change lanes Only if you are driving a truck or car
Physics
1 answer:
Vesnalui [34]3 years ago
5 0
Hello there!

Anytime you change lanes.


Hope this helps :)
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What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
Yuri [45]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

=>     \lambda  =  6.22 *10^{-7} \ m

       \lambda  =  622 nm

8 0
3 years ago
Sagutin ang mga sumusunod na tanong. Isulat ang iyong sagot sa sagutang papel.
Maru [420]

Answer:

ang mga nota opo naipalakpak ko ng maayos

7 0
3 years ago
BRAINLIEST AND 30 POINTS‼️‼️
kobusy [5.1K]

Answer:

802.3kilo joules of energy represents 191.75 kilo calorie

5 0
2 years ago
. Stephen learned that any two objects exert a gravitational force on each other.
viva [34]

Explanation:

Stephen learned that any two objects exert a gravitational force on each other.

If the distance between two objects triples, the gravitational force between

5 0
2 years ago
You are working on a laboratory device that includes a small sphere with a large electric charge Q. Because of this charged sphe
Margaret [11]

a)  q_shell = -Q ,  b)  q_shell = -Q

a) We can solve this exercise using Gauss's law

Ф = ∫ E. dA =  /ε₀

For this we use a Gaussian surface that takes advantage of the symmetry of the problem, we select a sphere where this force of the spherical plastic shell.

In this case, the electric field lines coincide with the radii of the sphere and the scalar product reduces to the algebraic product, the area of ​​the sphere

     A = 4 π r²

fi = E 4π r² = q_{int} /ε₀

apply this formula to our case, we have that the charge inside the Gaussian sphere is

   q_{int} = q_sphere + q_shell

the charge of the sphere is Q and the requirement is that there is no electric field outside the Gaussian sphere, for this, the net charge inside it must be zero

      0 = Q + q_shell

      q_shell = -Q

b) In Gauss's law, only the charge inside the Gaussian surface matters, not its position, therefore if the charge is not in the center the result remains the same.

     q_shell = -Q

Please check the attached attachment for the detailed answer.

Learn more about Gauss's law at

brainly.com/question/14773637

#SPJ4

8 0
2 years ago
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