Hello!
Pseudoscience in a sentence is "A pseudoscience is set of ideas based on theories put forth as scientific when they are not scientific."
Explanation:
(a) According to the law of conservation of energy,
Potential energy = Kinetic energy
mgh =
Putting the given values into the above formula as follows.
mgh =
h = 0.9 m
Therefore, the height H is 0.9 m.
(b) For the given situation,
Kinetic energy = work done by friction
u = 0.3
Thus, we can conclude that the coefficient of kinetic friction on the horizontal surface is 0.3.
Answer:
F' = 800 N
Explanation:
The electrical force between charges is 400 N.
The electrical force between two charges is given by :
![F=k\dfrac{q_1q_2}{r^2}](https://tex.z-dn.net/?f=F%3Dk%5Cdfrac%7Bq_1q_2%7D%7Br%5E2%7D)
If q₁' = 2q₁, new force becomes,
![F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N](https://tex.z-dn.net/?f=F%27%3Dk%5Cdfrac%7Bq_1%27q_2%27%7D%7Br%5E2%7D%5C%5C%5C%5CF%27%3Dk%5Cdfrac%7B2q_1%5Ctimes%20q_2%7D%7Br%5E2%7D%5C%5C%5C%5CF%27%3D2%5Ctimes%20F%5C%5C%5C%5CF%27%3D2%5Ctimes%20400%5C%5C%5C%5CF%27%3D800%5C%20N)
So, the new force becomes 800 N.
Answer:
maximum speed of the bananas is 18.8183 m/s
Explanation:
Given data
amplitude A = 23.195 cm
spring constant K = 15.2676 N/m
mass of the bananas m = 56.9816 kg
to find out
maximum speed of the bananas
solution
we know that radial oscillation frequency formula that is = √(K/A)
radial oscillation frequency = √(15.2676/23.195)
radial oscillation frequency is 0.8113125 rad/s
so maximum speed of the bananas = radial oscillation frequency × amplitude
maximum speed of the bananas = 0.8113125 × 23.195
maximum speed of the bananas is 18.8183 m/s
During the course of trajectory, the horizontal component of the velocity is <u>constant</u>