You, a 70 kg person, leap from a 10 m tall building and land feet first on a trampoline. The center of the trampoline where you
1 answer:
Answer:
1373.4 N/m
Explanation:
Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then
Also, F=gm hence the above formula is modified as
Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then
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12.8 rad
Explanation:
The angular displacement through which the wheel turned can be determined from the equation below:
(1)
where
Using these values, we can solve for from Eqn(1) as follows:
or
The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
where
is the angle between the directions of v and B.
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
. In this case, v and B are perpendicular, so 
, therefore we have:
2) In this second case, the angle between v and B is
. The charge is now 
, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
where
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
2) In this second case, the angle between v and B is