Answer:
6 seconds
Step-by-step explanation:
Given
y = - 12x(x - 6)
When the ball hits the ground then height of ball is zero
let y = 0 , that is
- 12x(x - 6) = 0
Equate each factor to zero and solve for x
- 12x = 0 ⇒ x = 0 ← when ball is first kicked
x - 6 = 0 ⇒ x = 6 ← when the ball hits the ground.
The ball hits the ground after 6 seconds
The graph shown in the picture is a hyperbola. It can be shown that the center lies on the line of symmetry. In this case, it can be seen that center of the hyperbola is at (3,-5). A hyperbola has an equation of x^2/a - y^2/b =1. a and b are the units between the two curves. a and b are both equal to 4. SInce the center is (3,-5), the equation of the parabola is (<span>x-3)^2/4 - (y+5)^2/4 =1.</span>
Answer:
10
Step-by-step explanation:
10 is the least of the numbers, it is the lowest
10<14,16,20,29
Answer: 0.75
Step-by-step explanation:
It is easier to divide if you get rid of the decimal, divide 375/5, and then add the decimal back.
N = population size
n = sample size
sigma = population standard deviation
xbar = sample mean
SE = standard error
fpc = finite population correction
In this case,
N = 200
n = 49
sigma = 14
xbar = 56
Since n/N = 49/200 = 0.245 is larger than 0.05, this means we must use a finite population correction factor. I'll use fpc in place of 'finite population correction'.
If we ignore the fpc, then the SE would be simply sigma/sqrt(n) = 14/sqrt(49) = 2.
However we cannot ignore the fpc. We must use it due to the fact that n/N > 0.05.
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Let's compute the fpc factor
fpc = sqrt((N-n)/(N-1))
fpc = sqrt((200-49)/(200-1))
fpc = 0.87108780834612
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With the fpc factor, we'll have the true SE to be SE = fpc*sigma/sqrt(n) = 0.87108780834612*14/sqrt(49) = 1.74217561669224
The final answer, accurate to 6 decimal places, is therefore 1.742176
