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Lorico [155]
3 years ago
11

The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the

same pressure?
Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

T_2=24.3^{\circ} C

Explanation:

Given that,

The volume of a sample of gas measured at 27 °C is 10.0 dm.

We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.

According Charles law,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where, T₂ is new temperature

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{9\times 27}{10}\\\\T_2=24.3^{\circ} C

So, the new temperature is 24.3^{\circ} C.

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1. You have 19.7 grams of a material and wonder how many moles were formed. Your
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The above does not look right because the grams do not cancel out. If it's not cancelled, it would be included in your final answer, but you're looking for moles not grams.

When setting up a stoichiometry equation, you have to put the same unit of measurement (ex- grams, cm, mm, etc.) on the numerator of one side and the denominator of the other side.

This would cancel out the unit.

For example: If you wanted to find out how much of 320 cm are in a meter.

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\frac{320cm}{1} × \frac{1 meter}{100 cm} = 3.2 m

Going back, your friend would have to switch the units from grams/moles to moles/grams. It would cancel out grams, which would leave moles. Therefore, moles will be included in your final answer.

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