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Lorico [155]
3 years ago
11

The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the

same pressure?
Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

T_2=24.3^{\circ} C

Explanation:

Given that,

The volume of a sample of gas measured at 27 °C is 10.0 dm.

We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.

According Charles law,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where, T₂ is new temperature

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{9\times 27}{10}\\\\T_2=24.3^{\circ} C

So, the new temperature is 24.3^{\circ} C.

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