Question

The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the same pressure?

Answer 1

Answer:

$T_2=24.3^{\circ} C$

Explanation:

Given that,

The volume of a sample of gas measured at 27 °C is 10.0 dm.

We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.

According Charles law,

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Where, T₂ is new temperature

$T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{9\times 27}{10}\\\\T_2=24.3^{\circ} C$

So, the new temperature is $24.3^{\circ} C$.