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Lorico [155]
3 years ago
11

The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the

same pressure?
Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

T_2=24.3^{\circ} C

Explanation:

Given that,

The volume of a sample of gas measured at 27 °C is 10.0 dm.

We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.

According Charles law,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where, T₂ is new temperature

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{9\times 27}{10}\\\\T_2=24.3^{\circ} C

So, the new temperature is 24.3^{\circ} C.

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Explain three path ways of respiration​
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Fill in the coefficients that will balance the following reaction:
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Explanation:

Given equation;

      NaC₂H₃O₂   +  Fe₂O₃   →   Fe(C₂H₃O₂)₃  +  Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

      aNaC₂H₃O₂   +  bFe₂O₃   →   cFe(C₂H₃O₂)₃  +  dNa₂O

a, b, c and d are the coefficients that  will balance the equation.

 conserving Na;    a  = 2d

                       C:     2a  = 6c

                       H:     3a  = 9c

                       O;      2a + 3b  = 6c + d

                       Fe:     2b = c

let a = 1

    solving:

      2a = 6c

       2(1) = 6c

          c = \frac{2}{6}  = \frac{1}{3}

      2b = c

          b = \frac{1}{2}  x \frac{1}{3} = \frac{1}{6}

     d = 2a + 3b - 6c = 2(1 ) + (3 x\frac{1}{6}  )  - (6  x  \frac{1}{3}) = \frac{1}{2}

Now multiply through by 6

  a = 6, b = 1, c = 2 and d = 3

             

                6NaC₂H₃O₂   +  Fe₂O₃   →   2Fe(C₂H₃O₂)₃  +  3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

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