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docker41 [41]
1 year ago
12

How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess P4)?

Chemistry
1 answer:
ludmilkaskok [199]1 year ago
3 0

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

#SPJ9

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Explanation:

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<u><em>The ΔH is 5.5 kJ/mol and the reaction is endothermic.</em></u>

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