Question

How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess P4)?

Answer 1

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

How to calculate moles?

The balanced chemical equation is

$P_{4} + 10Cl_{2} = 4PCl_{5}$

The mass of clorine is m($Cl_{2}$) = 58.0 g

The amount of clorine is n($Cl_{2}$) = m($Cl_{2}$)/M($Cl_{2}$) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of $Cl_{2}$ yield 4 moles of $PCl_{5}$;

0.817 of $Cl_{2}$ yield x moles of $PCl_{5}$

n($PCl_{5}$) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

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