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mestny [16]
3 years ago
11

By examining the diagram, which of the following is NOT needed for photosynthesis:

Chemistry
1 answer:
WARRIOR [948]3 years ago
8 0
It’s oxygen

The formula is carbon dioxide + water + sunlight = oxygen + glucose

Therefore, you don’t need oxygen as it’s a product
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Sulfur burns in the air to form 33.6L of sulfur dioxide. (S = 32, O =16, 64g of sulfur dioxide has 22.4L, 32g of oxygen has 22.4
ivolga24 [154]

The mass of oxygen reacted/required in this reaction is obtained as 48g.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with mass- volume or mass - mole relationship which ultimately depends on the balanced reaction equation.

Now, we have the reaction; S + O2 ------>SO2

If 1 mole of sulfur dioxide contains 22.4 L

x moles of sulfur dioxide contains 33.6L

x = 1.5 moles of sulfur dioxide.

Since the reaction is 1:1, the number if moles of oxygen required/reacted is 1.5 moles.

Mass of oxygen required/reacted = 1.5 moles * 32 g/mol = 48g

Learn more anout stoichiometry: brainly.com/question/9743981

8 0
2 years ago
PLEASE HELP!!!!!!!
KonstantinChe [14]

Answer: The gas generated by two antacid tablets has a smaller volume.

Explanation:

Since the antiacid is the limiting reagent, we know that the more tablets there are, the more gas there will be.

This means that there will be more gas generated by the four antiacid tablets when compared to the two antiacid tablets, which gives us that the gas generated by the two antiacid tablets has a smaller volume.

6 0
2 years ago
A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien
Paha777 [63]
It would be C because It will have a lower activation energy than Trial A.
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3 years ago
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A graduated cylinder is filled with 34.4 mL of water. A toy Car that weighs 43.672-g is Gently placed in the cylinder and the wa
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Answer:9.49g/mL

Explanation:

Mass of toy = 43.672g

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Volume of toy + volume of water = 39mL

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8 0
2 years ago
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A.) Phosphate ion or Orthophosphate
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e.) Iron
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