Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
7:05, 7:15 , and 7:12 i hope this helps
Answer:
d.exponential is answer
Step-by-step explanation:
I hope it's helpful!
-Answer:
(-3. -6)
Step-by-step explanation:
G (3,6)
x axis reflect
G' (3, -6)
y axis reflect
G'' (-3. -6)
The time that the ball is in the air is 2x the time that it takes to reach the maximum value.
In order to find the time at the max value you use the equation -b/2a where b is the value attached to the t and a is the value attached to t^2.
therefore, the time at the max value is -180/(2)(-16)=5.625 seconds
Total time= (5.625)(2)=11.25
