<span>moles glucose = 19 g / 180 g/mol= 0.105
M = 0.105 / 0.100 L = 1.05
moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216
New concentration = 0.0216 /0.500 L = 0.0432 M
moles in 100 mL = 0.100 L x 0.0432 = 0.00432
mass = 0.00432 x 180 g/mol= 0.778 g</span>
<u>Answer: </u>The volume occupied by
at STP is 0.56 L.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

We are given:
Given mass of oxygen = 0.80 g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:

<u>At STP:</u>
1 mole of a gas occupies 22.4 L of volume.
So, 0.025 moles of oxygen gas will occupy =
of volume.
Hence, the volume occupied by
at STP is 0.56 L.
Answer:
Point C
Explanation:
Point C has the greatest potential energy because it is at that point that the riders will have maximum height
Answer: -
1.34 L
Explanation: -
Initial Pressure P 1 = 39.1 bar
Initial Temperature T 1 = 643 K
Let the initial volume be V 1.
Final pressure P 2 = 87.0 bar
Final temperature T 2 = 525 K.
Final volume V 2 = 0.492 L
Using the equation


Plugging in the values
We have
V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)
= 1.34 L
Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K
The volume of 10 grams of frozen water is more than the volume of 10 grams of liquid water