Question

Please help me Evaluate 3 + jk + k^3 when j=2 and k=6

Answer 1

231

substitute the given values for j and k into the expression

= 3 + (2 × 6) + (6)³ = 3 + 12 + 216 = 231

Answer 2

$3 + jk + {k}^{3} = \\ = 3 + 2 \times 6 + {6}^{3} = \\ = 3 + 12 + 6 \times 6 \times 6 = \\ = 15 + 36 \times 6 = \\ = 15 + 216 = \\ = 231$