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3 years ago

According to the FDA, products labeled gluten-free must contain less than _______ of gluten.

Chemistry

2 answers:

Evgesh-ka [11]3 years ago

6 0

Answer: 20 milligram per kilo gram of food.

Explanation:

FDA: Food and drug Administration

According to FDA, product labelled as gluten free must contain 20 parts per million gluten. This also means that 20 milligram of gluten per kilo gram of food. or we can also say that 20 milligrams of gluten per 35.27 ounce of food.

Hence,the correct answer is option (c).

Svet_ta [14]3 years ago

3 0

According to the FDA, products labeled gluten-free must contain less than 20 milligrams of gluten

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Correct Answer: A. Science relies on observation, measurement, and experimentation.

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jarptica [38.1K]

Answer:

a. Too close to zero

b. ΔS > 0

c. Too close to zero

d. ΔS < 0

e. ΔS > 0

Explanation:

In order to answer this question we need to compare the change in number of mol in the gas state for the products vs the reactants.

An increase in number moles gas leads to a positive change in entropy. Conversely a decrease will mean ΔS is negative.

Now we can solve the parts in this question.

a. H₂ (g) + F₂ (g) ⇒ 2 HF (g)

We have no change in the number of moles gas products minus reactants. Therefore is too close to zero to decide since there is no change in mol gas.

b. 2 SO₃ ( g) ⇒ 2 SO₂ (g) + O₂ (g)

We have three moles of gas products starting with 2 mol gas SO₂, therefore ΔS is positive.

c. CH₄ (g) + 2 O₂ (g) ⇒ CO₂ (g) + 2 H₂O (g)

Again, we have the same number of moles gas in the products and the reactants (3), and it is too close to zero to decide

d. 2 H₂S (g) + 3 O₂(g) ⇒ 2 H2O (g) + 2 SO₂ (g)

Here the change in number of moles gas is negative ( -1 ), so will expect ΔS < 0

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aliya0001 [1]

Answer:

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Explanation:

Given;

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Work done on the system, W = -311 J (negative because work was done on the system)

change in internal energy of the system, Δ U = ?

First law of thermodynamics states that the change in internal energy of a system (ΔU) equals the net heat transfer into the system (Q) minus the net work done by the system (W).

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