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4 years ago

9

What is the deflection equation for a simply supported beam with a uniformly distributed load?

1 answer:

Bingel [31]4 years ago

5 0

Answer:

$\Delta _{max}=\dfrac{5wL^4}{384EI}$

Explanation:

Given that

Load is uniformly distributed load and beam is simply supported.

Ra + Rb= wL

Ra = Rb =wL / 2

Lets x is measured from left side,then the deflection of beam at any distance x is given as

$\Delta _x=\dfrac{wx}{24EI}(L^3-2Lx^2+x^3)$

The maximum deflection of beam will at x = L/2 (mid point )

$\Delta _{max}=\dfrac{w\times \dfrac{L}{2}}{24EI}(L^3-2L\times \left (\dfrac{L}{2}\right)^2+\left(\dfrac{L}{2}\right)^3)$

$\Delta _{max}=\dfrac{5wL^4}{384EI}$

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Oil with a kinematic viscosity of 4 10 6 m2 /s fl ows through a smooth pipe 12 cm in diameter at 2.3 m/s. What velocity should w

Setler79 [48]

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By Removing square rots on both sides

${\frac{V_{5}XD_{5} }{v_{5}}}$ = ${\frac{V_{12}XD_{12} }{v_{12}}}$

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4 0

4 years ago

The current in the wires of a circuit is 90 milliAmps. If the resistance of the circuit were doubled (with no change in voltage)

melomori [17]

Answer:

$I = 45mA$

Explanation:

Given

$I = 90mA$ --- Current

Required

Determine the new current when resistance is doubled

Using $V = IR$

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When resistance is doubled and voltage remains unaltered, we have:

$V = I* 2R$

2R represents the new resistance and I represents the new current

Equate both values of V

$90mA * R = I* 2R$

Make I the subject

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$I = \frac{90mA }{2}$

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3 years ago