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Katen [24]
3 years ago
10

Pls help don’t understand this at all

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

You need to get a common denominator first. The least common multiple of 3 and 5 is 15. You need to multiply 4x/5 By 3 so the denominator is 15. That would be 12x/15. Then you need to multiply 2x/3 by 5 to get the denominator to be 15. That would be 10x/15.

12x/15 - 10x/15= 2x/15

The answer is D. Hope this helped

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Solve for x 0°&lt;x&lt;360<br>3cos2x +sinx=1​
BartSMP [9]

Step-by-step explanation:

3cos2x +sinx=1

3(1-2sin²x)+sinx=1

3-6sin²x+sinx=1

sinx(-6sinx+1)=1

either

sinx=1

sinx=sin(90)

:.x=90

or

-6sinx+1=1

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8 0
3 years ago
Help me plz this is hard
cricket20 [7]

you first use distributive property for the multiplication

[(2*4x)-(2*11)]+9=19

8x-22+9=19

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8x=19+22-9

8x=(19+22)-9

8x=41-9

8x=32

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x=4

3 0
4 years ago
in the figure above, bc and ad are parallel, ab and ec are parallel, cd=ce, and the measure of angle abc is 115 degrees. what is
bonufazy [111]

Answer:

"in the figure above" ?

7 0
3 years ago
To find the quotient 4 divided1/5 multiply 4 by
Alinara [238K]

Answer:

5

Step-by-step explanation:

When dividing numbers by fractions, we can simply multiply the  umber by the reciprocal of the decimal. So,

4 ÷ 1/5 = 4 × (reciprocal of 1/5)

A reciprocal of a number is the same number written under 1. aka, 1 divided by that number, which simply is flipping the numerator and denominator of a number.

So the reciprocal of 1/5 is 5/1 = 5.

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hope it was useful!

5 0
3 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
3 years ago
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