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34kurt
3 years ago
6

What is the average kinetic energy of 1 mole of gas at 102 degree celsius

Chemistry
2 answers:
Simora [160]3 years ago
6 0

Answer:

The average kinetic energy of the gas is 4.678 kJ/mol.

Explanation:

Average kinetic energy of the gas id defined as measure of an average kinetic energy possessed by each particle of the gas.

It is given as:

K=\frac{3}{2}RT (Average kinetic energy per mole)

K=\frac{3}{2}kT (Average kinetic energy per molecule)

R = Universals gas constant8.314 J /mol K

T = temperature of the gas

k = Boltzmann constant = 1.38\times 10^{-23} J/K

The average kinetic energy of 1 mole of gas at 102°C:

T = 102°C = 375.15 K[/tex]

K=\frac{3}{2}\times 8.314 J/mol K\times 375.15 K=4,678.49 J/mol=4.678 kJ/mol

The average kinetic energy of the gas is 4.678 kJ/mol.

Firlakuza [10]3 years ago
5 0
<span>R= 8.314 J/mol K T= 273 + 102 = 375K</span><span>

= (3/2) x 8.314 x 375 = 4680 J/mol</span>
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An unknown noble gas has a density of 5.84 g dm-3 at STP. Calculate its molar mass, and so identify the gas.
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The noble gas is Xenon and its molar mass is 131 g/mol.

<h3>What is the molar mass of the noble gas?</h3>

The molar mass of the noble gas is determined as follows;

Let molar mass of unknown gas be M, and mass of gas be m

Density of the noble gas, ρ = 5.8 g/dm³

density = m/V

At STP;

  • temperature, T = 273.15 K
  • pressure, P = 1 atm
  • molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹

From ideal gas equation:

PV = nRT

where n = m/M

PV = mRT/M

M = mRT/PV

M =  0.0821 * 273.15 * 5.84/1

Molar mass of the noble gas = 131 g/mol

The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.

Learn more about molar mass at: brainly.com/question/837939

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1 year ago
Cheryl kept a potted plant near a window. After two days, she observed that the plant had drooped as shown.
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For an ideal gas, classify the pairs of properties as directly or inversely proportional. You are currently in a sorting module.
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the result for the following are (a) P is directly proportional to n

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An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
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Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

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Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

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There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


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