The noble gas is Xenon and its molar mass is 131 g/mol.
<h3>What is the molar mass of the noble gas?</h3>
The molar mass of the noble gas is determined as follows;
Let molar mass of unknown gas be M, and mass of gas be m
Density of the noble gas, ρ = 5.8 g/dm³
density = m/V
At STP;
- temperature, T = 273.15 K
- pressure, P = 1 atm
- molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹
From ideal gas equation:
PV = nRT
where n = m/M
PV = mRT/M
M = mRT/PV
M = 0.0821 * 273.15 * 5.84/1
Molar mass of the noble gas = 131 g/mol
The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.
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A watering the plant. Plants wilt or droop when there’s not enough water because it helps reduce the amount of a surface area
Answer:
the result for the following are (a) P is directly proportional to n
(b) V is directly proportional to T (c) P is directly proportional to T (d) T is inversly proportional to V (e) P is inversely proportional to V
Answer:- Formula of the hydrate is
and it's name is Iron(III)sulfate pentahydrate.
Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.
Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.
We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

= 

= 
Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.
= 1
= 5
There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is
and the name of the hydrate is Iron(III)sulfate pentahydrate.
I believe the answer is A