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Tasya [4]
3 years ago
15

Assuming fixed shape when heated?​

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

Assuming that the atmospheric pressure is standard, the temperature will rise steadily until it reaches 100°C

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How many grams of barium sulfate form when 35.0 ml of 0.160 m barium chloride reacts with 58.0 ml of 0.065 m sodium sulfate? do
vazorg [7]

Barium sulfate weighs 0.88 grams per gram.

Mass:

A physical body's overall composition is measured by its mass.

Inertia, or the body's resistance to acceleration in the presence of a net force, is also measured by it.

The mass of a thing also affects how strongly it attracts other bodies through gravity.

In the SI, the kilogram serves as the basic mass unit (kg).

This information

Moles of BaCl2 equal 5.6 x 103 (35 x 0.160 / 1000)

sodium sulfate moles equal 58 x 0.065, or 3.77 x 103,

Na2SO4 with BaCl2 ——————————-> 2NaCl plus BaSO4

Na2SO4 is the limiting agent here.

Therefore, the product relies on limiting reagent.

1 mol of Na2SO4 produces 1 mol of BaSO4.

0.00377 moles of BaSO4 is one mole.

moles = mass / molar mass of BaSO4.

0.00377 = mass / 233.4

BaSO4 mass is 0.88 g.

So, 0.88 grams of barium sulfate make up one gram.

To know more about the mass visit:

brainly.com/question/28204586

#SPJ4

3 0
1 year ago
PLEASE HELP
Sergio [31]

Answer:

C. The Protons

5 0
3 years ago
Read 2 more answers
Label the parts of the atom.<br><br> Which atomic particle determines the identity of the atom?
zavuch27 [327]
A: Electron
B: Neutron
C: Proton
3 0
3 years ago
811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of
Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

  • Provided heat (Q): 811.68 J
  • Mass of the metal (m): 95 g
  • Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0
3 years ago
A sample of gas occupies a volume of 73.7 mL. As it expands, it does 133.7 J of work on its surroundings at a constant pressure
katen-ka-za [31]
In thermodynamics<span>, </span>work<span> performed by a system is the energy transferred by the system to its surroundings. It can be calculated by the expression:
</span>
W = PdV

Integrating,

We will have,

W = P(V2 - V1)
133.7 (1 litre-atm / 101.325 Joule) ( <span>760 Torr / atm ) </span>= 783 (V2 - .0737 )
V2 = 1.35 L

Hope this answers the question.  Have a nice day.


7 0
3 years ago
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