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Tasya [4]
3 years ago
15

Assuming fixed shape when heated?​

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

Assuming that the atmospheric pressure is standard, the temperature will rise steadily until it reaches 100°C

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7. Calculate the amount of energy required heat 100.g to <br> H2O(s) changes to H2O(l) at 0°C
Brrunno [24]

Answer:

33300J

Explanation:

Given parameters:

Mass of ice  = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

 So;

            H  = mL

m is the mass

L is the latent heat of melting ice

  Now, insert the parameters and solve;

            H = mL

 mass from gram to kilogram;

            100g gives 0.1kg

  H = 0.1 x 3.33 x 10⁵ = 33300J

8 0
2 years ago
If an iron atom loses two electrons, the name of the iron ion is
adoni [48]
If iron atom looses 3 electrons, it forms Fe+3 (ferric) and if iron looses 2 electrons, it forms Fe+2(ferrous). Hope this helps!
5 0
3 years ago
Read 2 more answers
A. Find the pH and pOH of a solution having 6.6 x 10-6 M
Luba_88 [7]

Answer:

iudshfuhf98

Explanation:

5 0
3 years ago
During your reaction, you added 0.3 mL concentrated H2SO4 (18.4 M) as the catalyst. At the end of the reaction, you need to add
sattari [20]

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s)  --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡  'A' M  of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094  M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂  the subject of the formula;we have:

V_2 = \frac{18.4*0.3}{0.094}

V₂ = 58.72 mL

4 0
3 years ago
What do Ivan Pavlov and Erik Erikson have in common?
Vikentia [17]

Answer:

I don't know the exact answer you are looking for

7 0
2 years ago
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