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hodyreva [135]
3 years ago
7

A fully braced structural member in a building is subjected to several different loads, including roof loads of D = 5 k and L_r

= 7 k; floor loads of D = 6 k and occupancy L = 15 k; S = 18 k; and W = 17 k and E = 12 k (resulting from overturning forces on the lateral-force-resisting system). Consider the ASD load combinations described in Sec. 2.17 and assume the wind and seismic loads act in the same direction as the gravity toads. Find: The critical ASD combination of loads.

Engineering
1 answer:
allochka39001 [22]3 years ago
7 0

Answer: 37.4K

Explanation:

See attachment

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A steel plate has a hole drilled through it. The plate is put into a furnace and heated. What happens to the size of the inside
djverab [1.8K]

Answer:

The diameter increases

Explanation:

The expansion in the metal is uniform in every dimension

4 0
3 years ago
Can be used to eliminate rubbing friction of wheel touching frame. 1.Traction 2.Thrust washer
Vilka [71]

Answer:

thrust washer

can be used to eliminate rubbing friction of wheel touching frame

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What is the metal removal rate when a 2 in-diameter hole 3.5 in deep is drilled in 1020 steel at cutting speed of 120 fpm with a
Studentka2010 [4]

Answer:

a) the metal removal rate is 14.4 in³/min

b) the cutting time is 0.98 min

Explanation:

Given the data from the question

first we find the rpm for the spindle of the drilling tool, using the equation

Ns = 12V/πD

V is the cutting speed(120 fpm) and D is the diameter of the hole( 2 in)

so we substitute

Ns = 12 × 120 / π2

Ns = 1440 / 6.2831

Ns = 229.18 rmp

Now we find the metal removal rate using the equation

MRR = (πD²/4) Fr × Ns

Fr is the feed rate( 0.02 ipr ),

so we substitute

MRR = ((π × 2²)/4) × 0.02 × 229.18

MRR = 14.3998 ≈ 14.4 in³/min

Therefore the metal removal rate is 14.4 in³/min

Next we find the allowance for approach of the tip of the drill

A = D/2

A = 2/2

= 1 in

now find the time required to drill the hole

Tm = (L + A) / (Fr × Ns)

Lis the the depth of the hole( 3.5 in)

so we substitute our values

Tm = (3.5 + 1) / (0.02 × 229.18  )

Tm = 4.5 / 4.5836

Tm = 0.98 min

Therefore the cutting time is 0.98 min

8 0
3 years ago
A six-lane freeway (three lanes in each direction) with a 5.5% uphill grade 1.5 miles long has 10-ft lanes and obstructions 5 ft
sertanlavr [38]
The answer would be:
A. LOS B
4 0
3 years ago
Read 2 more answers
A 4-kW electric heater runs for 2 hours to raise the room temperature to the desired level. Determine the amount of electric ene
Anna35 [415]

Answer:

Q' = 8 KW.h

Q'=28800 KJ

Explanation:

Given that

Heat Q= 4 KW

time ,t = 2 hours

The amount of energy used in KWh given as

Q ' = Q x t

Q' = 4 x  2 KW.h

Q' = 8 KW.h

We know that

1 h = 60 min = 60 x 60 s  = 3600 s

We know that W  = 1 J/s

The amount of energy used in KJ given as

Q' = 8 x 3600 = 28800 KJ

Therefore

Q' = 8 KW.h

Q'=28800 KJ

6 0
3 years ago
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