Answer:
Gs = 2.647
e = 0.7986
Explanation:
We know that moist unit weight of soil is given as

where,
= moist unit weight of the soil
Gs = specific gravity of the soil
S = degree of saturation
e = void ratio
= unit weight of water = 9.81 kN/m3
From data given we know that:
At 50% saturation,
puttng all value to get Gs value;

Gs - 1.194*e = 1.694 .........(1)
for saturaion 75%, unit weight = 17.71 KN/m3

Gs - 1.055*e = 1.805 .........(2)
solving both equations (1) and (2), we obtained;
Gs = 2.647
e = 0.7986
Answer:
The required pumping head is 1344.55 m and the pumping power is 236.96 kW
Explanation:
The energy equation is equal to:

For the pipe 1, the flow velocity is:

Q = 18 L/s = 0.018 m³/s
D = 6 cm = 0.06 m

The Reynold´s number is:


Using the graph of Moody, I will select the f value at 0.0043 and 335339.4, as 0.02941
The head of pipe 1 is:

For the pipe 2, the flow velocity is:

The Reynold´s number is:


The head of pipe 1 is:

The total head is:
hi = 1326.18 + 21.3 = 1347.48 m
The required pump head is:

The required pumping power is:

Answer:
See explaination
Explanation:
Kindly check attachment for the step by step solution of the given problem.
Do you have a picture of the question?
Answer: precision
Explanation: Because accuracy is where you keep on getting it right but precision is where you get closer and closer