1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SpyIntel [72]
3 years ago
11

Hello, so I have a watch and I don't know where the plugin for the charger is, or what brand it is. Please do help and please DO

N'T STEAL THE POINTS. IM TALKING TO YOU CANCER01 ! ANSWER IT RIGHT OR GET REPORTED. THIS IS YOUR FIRST AND LAST WARNING. IF YOU DARE STEAL MY POINTS IM GIVING TO PEOPLE WHO ANSWER WITH THE RIGHT INFORMATION AND ONLY GET HAVE THE POINTS DUE TO SCAMMERS AND POINT STEALERS I WILL REPORT YOU RIGHT AWAY SO STOP PLAYING WITH ME, THIS IS WHY AS SOON AS I SEE ANOTHER APP MORE RELIABLE AND TRUSTWORTHY THAN BRAINLY, IM DITCHING THIS DUMP BECAUSE PEOPLE LIKE YOU RUIN THE REPUTATION OV BRAINLY, GIVING PEOPLE THE WRONG ANSWER AND PUTTING IN NONE SINCE ALL FOR POINTS AND RANKS. THIS CAN BE A BETTER COMMUNITY IF YOU PEOPLE DIDN'T EXIST ON BRAINLY. NOW TO ALL THE SCAMMERS OUT THERE, ANSWER THIS RIGHT OR LEAVE. THATS ALL I GOT TO SAY.
And to all the people who are considerate of others who need help and take time out of your day to help them, I just want to say...


Thank you, you guys are the best, people like you can help brainly become a better place, and forget those people who steal points for their ranks because they don't know what's it's like to practically be a online tutor because you know what its like to be stuck on a hard question. You guys are the reason why I get through the hard questions on the quizzes. You guys are the reason why people pass. You guys are the glues that holds brainly together. You guys are the reason brainly is still standing today. So I would like to take this time to say... Thank you. For all you do. ❣. ​
Engineering
1 answer:
miss Akunina [59]3 years ago
5 0

Thank you, you guys are the best, people like you can help brainly become a better place, and forget those people who steal points for their ranks because they don't know what's it's like to practically be a online tutor because you know what its like to be stuck on a hard question. You guys are the reason why I get through the hard questions on the quizzes. You guys are the reason why people pass. You guys are the glues that holds brainly together. You guys are the reason brainly is still standing today. So I would like to take this time to say... Thank you. For all you do. ❣.

You might be interested in
PLZ ANSWER SOON!!!
slava [35]

Answer:

You're answer would be "D. Perform all of the above"

Explanation:

Have a Blessed Day (Mark Brainliest!)

4 0
3 years ago
Read 2 more answers
calculate force and moment reactions at bolted base O of overhead traffic signal assembly. each traffic signal has a mass 36kg,
Igoryamba

Answer:

The free body diagram of the system is, 558 368 368 508 O ?? O, Consider the equilibrium of horizontal forces. F

Explanation:

I hope this helps you but I think and hope this is the right answer sorry if it’s wrong.

7 0
3 years ago
An inductor of ????=6.95 H with negligible resistance is placed in series with a ℰ=12.5 V battery, a ????=3.00 Ω resistor, and a
elena-14-01-66 [18.8K]

Answer:

a) I=0 b) 4.17V c) 0.354 A d) 14.5s

Explanation:

a) consider circuit in the attachment

i(t)= E/R (1- e^(-t/RL))

i(0)= 12.5/3×(1-e^(0/RL))

i(0)=0

b) at t⇒∞

i(∞)= 12.5/3× (1- e^(-∞/RL))

    = 4.17V

c) 1/RL= 1/(6.95×3)= 0.0479616

i(1.85) = 12.5/3 × (1- e^(-1.85×0.0479616)

         = 0.354A

d) I/2= I (1- e^(-t/RL))

t= - RL ln0.5

t= - 3×6.95 × (-0.693)

t= 14.5 s

8 0
4 years ago
Find the time-domain sinusoid for the following phasors:_________
sattari [20]

<u>Answer</u>:

a.  r(t) = 6.40 cos (ωt + 38.66°) units

b.  r(t) = 6.40 cos (ωt - 38.66°) units

c.  r(t) = 6.40 cos (ωt - 38.66°) units

d.  r(t) = 6.40 cos (ωt + 38.66°) units

<u>Explanation</u>:

To find the time-domain sinusoid for a phasor, given as a + bj, we follow the following steps:

(i) Convert the phasor to polar form. The polar form is written as;

r∠Ф

Where;

r = magnitude of the phasor = \sqrt{a^2 + b^2}

Ф = direction = tan⁻¹ (\frac{b}{a})

(ii) Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid (r(t)) as follows:

r(t) = r cos (ωt + Φ)

Where;

ω = angular frequency of the sinusoid

Φ = phase angle of the sinusoid

(a) 5 + j4

<em>(i) convert to polar form</em>

r = \sqrt{5^2 + 4^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{4}{5})

Φ = tan⁻¹ (0.8)

Φ = 38.66°

5 + j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

(b) 5 - j4

<em>(i) convert to polar form</em>

r = \sqrt{5^2 + (-4)^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{-4}{5})

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

5 - j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(c) -5 + j4

<em>(i) convert to polar form</em>

r = \sqrt{(-5)^2 + 4^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{4}{-5})

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

-5 + j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(d) -5 - j4

<em>(i) convert to polar form</em>

r = \sqrt{(-5)^2 + (-4)^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{-4}{-5})

Φ = tan⁻¹ (0.8)

Φ = 38.66°

-5 - j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

3 0
3 years ago
Technician A says inspecting the operation of the automatic emergency brake system helps determine whether the spring brakes wil
laila [671]

Answer: Both Technicians

Explanation:

When testing a spring break it is advisable to Step on and off the brake, with the engine off, the parking brake knob is expected to pop out when air pressure falls between 20-40 psi.

Go under the vehicle and pull the spring brakes.

Turn on the engine back and pump the brake pedal down to the floor. To test the spring breaks

8 0
3 years ago
Other questions:
  • True or false? Don't break or crush mercury-containing lamps because mercury powder may be released.
    8·1 answer
  • In a right triangle, the square of the length of one side is equal to the sum of the squares of the lengths of the other two sid
    10·1 answer
  • Following in each of the following three mechanisms, the crank is the input link, 1) draw vectors with labeled angles 2) write t
    11·1 answer
  • Why are open systems harder to study than closed systems?​
    6·1 answer
  • A particular op amp using ±15-V supplies operates linearly for outputs in the range−14 V to+14 V. If used in an inverting amplif
    13·1 answer
  • 7. The "3 second rule" is the time you should pause at an intersection marked with a stop sign.
    6·1 answer
  • If the channel-Length modulation effect is neglected, ID in the saturation region is considered to be independent of VDS
    14·1 answer
  • If the driver gear has 5 teeth and the driven gear has 10 teeth,what is the gear ratio?​
    13·2 answers
  • Compression is maintained during combustion because on top of the motor is a _____
    7·1 answer
  • A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy (Animated Figure 9.8) is heated to 250°C; at this temperature it is entirely an
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!