Answer:
you fill the hole so there is no more cat
Answer:
I have solved the problem below. I hope it will let you clear the concept.
For any inquiries ask me in the comments.
Explanation:
Answer:
It is a type of ANOVA that can analyze several independent variables at the same time.
Explanation:
This is the statement that correctly describes the n-way analysis of variance (ANOVA). ANOVA is a type of analysis of variance that can analyze several independent variables at the same time. In this type of analysis, a dependent variable is measured by different levels of independent variables. When the results are obtained, these are assumed to be the consequence of the different levels of the independent variables, plus random error. The computation necessary for this analysis can be done in most types of statistical software.
Answer:
Below is the desired C++ program for the problem. Do feel free to edit it according to your preference
Explanation:
#include <iostream>
#include <vector>
using namespace std;
void ExactChange(int userTotal, vector<int> &coinVals) {
coinVals.reserve(5);
coinVals[0] = userTotal / 100;
userTotal %= 100;
coinVals[1] = userTotal / 25;
userTotal %= 25;
coinVals[2] = userTotal / 10;
userTotal %= 10;
coinVals[3] = userTotal / 5;
userTotal %= 5;
coinVals[4] = userTotal;
}
int main() {
vector<int> coins;
int value;
cin >> value;
if (value <= 0) {
cout << "no change" << endl;
} else {
ExactChange(value, coins);
if (coins[0] != 0) cout << coins[0] << " " << (coins[0] == 1 ? "dollar" : "dollars") << endl;
if (coins[1] != 0) cout << coins[1] << " " << (coins[1] == 1 ? "quarter" : "quarters") << endl;
if (coins[2] != 0) cout << coins[2] << " " << (coins[2] == 1 ? "dime" : "dimes") << endl;
if (coins[3] != 0) cout << coins[3] << " " << (coins[3] == 1 ? "nickel" : "nickels") << endl;
if (coins[4] != 0) cout << coins[4] << " " << (coins[4] == 1 ? "penny" : "pennies") << endl;
}
return 0;
}
