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alexgriva [62]
2 years ago
14

Damian mixed two samples together: a

Chemistry
1 answer:
lesantik [10]2 years ago
3 0

Answer:C

Explanation:

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How many moles of sulfur are needed to react completely with 1.2 mol of O2?
valkas [14]
<span>Quantity can always be used the same way as moles when interpreting balanced chemical equations.</span>
6 0
3 years ago
Ending Transsmission definition<br> pls put the definition
sdas [7]

Answer:

When the act or process of a transmission stops

Explanation:

7 0
3 years ago
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How many moles of copper Il sulfide can be produced from 2.8 moles of sulfur? Cu + S --&gt; CuS​
Kamila [148]

Answer: 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

Explanation:

The balanced chemical reaction is:

Cu+S\rightarrow CuS  

According to stoichiometry :

1 mole of S produce =  1 mole of copper (Il) sulfide (CuS)

Thus 2.8 moles of S will produce=\frac{1}{1}\times 2.8=2.8moles of copper (Il) sulfide (CuS)

Thus 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

5 0
3 years ago
What is the volume of 13.21 g of ethane gas (C2H6) at STP?
yuradex [85]

The volume at STP : 9.856 L

<h3>Further explanation</h3>

Given

Mass of ethane : 13.21 g

Required

The volume at STP

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

mol ethane(C2H6) :

= mass : molar mass

= 13.21 g : 30 g/mol

= 0.44

Volume at STP :

= 0.44 x 22.4 L

= 9.856 L

6 0
3 years ago
A. Density of Liquids
morpeh [17]

Answer:

Mass of liquid: 20.421g

Density= 1.0109405940594 g/mL

Explanation:

Mass of liquid

To find mass of liquid you take the mass of beaker + liquid (171.223g) and subtract it from the Mass of beaker (beaker without the water). The difference is the answer.

171.223g - 150.802g = 20.421g

Density

To find density you use the formula Mass/Volume. Take the Volume given, and the mass of the liquid you just found.

20.421mL/20.421g = 1.0109405940594 g/mL

5 0
2 years ago
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