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4 years ago

DIRECTIONS: Use the Word Bank to answer the questions below. For questions 2 and 3 circle the correct choice.

Chemistry

1 answer:

Angelina_Jolie [31]4 years ago

8 0

Explanation:

1. Electrons surround the nucleus in defined regions called orbits.

2. The shells further away from the nucleus are larger and can hold more electrons.

3. The shells closer to the nucleus are smaller and can hold less electrons.

4. The closest shell (closest to the nucleus) can hold a maximum of two electrons.

5. Once the first shell is full, the second shell begins to fill. It can hold a maximum of eight electrons.

6. Once the second shell is full, the third shell begins to fill.

7. Once the third shell contains Eighteen electrons, the fourth shell begins to fill.

8. The arrangement of electrons in shells around the nucleus is referred to as an atom's electronic configuration.

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Using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (C6H6).

Anna007 [38]

Answer:

ΔH = -976.5 kJ

Explanation:

For the reaction given, there are 2 moles of benzene (C6H6). The heat of this reaction is -6278 kJ, which means that the combustion of 2 moles of benzene will lose 6278 kJ of heat. It is an exothermic reaction.

The value of ΔH, the enthalpy, is a way of measurement of the heat, and it depends on the quantity of the matter (number of moles).

So, 24.3 g of benzene has :

n = mass/ molar mass

n = 24.3/78.11

n = 0.311 moles

2 moles ------------ -6278 kJ

0.311 moles ----------- x

By a simple direct three rule:

2x = -1953.08

x = -976.5 kJ

3 0

3 years ago

Combine the two half-reactions that give the spontaneous cell reaction with the smallest E∘. Fe2+(aq)+2e−→Fe(s) E∘=−0.45V I2(s)+

Iteru [2.4K]

Answer: The spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

Explanation:

We are given:

$E^o_{(Fe^{2+}/Fe)}=-0.45V\\E^o_{(I_2/I^-)}=0.54V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, iodine will always undergo reduction reaction, then copper and then iron.

The equation used to calculate electrode potential of the cell is:

$E^o_{cell}=E^o_{oxidation}+E^o_{reduction}$

The combination of the cell reactions follows:

Case 1:

Here, iodine is getting reduced and iron is getting oxidized.

The cell equation follows:

$I_2(s)+Fe(s)\rightarrow Fe^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=0.45+0.54=0.99V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 2:

Here, iodine is getting reduced and copper is getting oxidized.

The cell equation follows:

$I_2(s)+Cu(s)\rightarrow Cu^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$ $E^o_{oxidation}=-0.34V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=-0.34+0.54=0.20V$

Thus, this cell will give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 3:

Here, copper is getting reduced and iron is getting oxidized.

The cell equation follows:

$Cu^{2+}(aq.)+Fe(s)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)$ $E^o_{reduction}=0.34V$

$E^o_{cell}=0.45+0.34=0.79V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Hence, the spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

7 0

3 years ago

Help I can’t figure it out.

makkiz [27]

I think it’s a, it has to be

4 0

3 years ago

Read 2 more answers

What Is A Sublimation

kondaur [170]

Answer:

sublimation is the transition of a substance directly from the solid to the gas phase without passing throught the intermedate liquid phase

such as the following

dry ice

air fresheners

freese drying

moth balls

Explanation:

5 0

3 years ago

Read 2 more answers

A 1500 L weather balloon is at 'a temperature of 290 K on the ground. As it rises the

myrzilka [38]

Answer:

1086.2 L

Explanation:

The computation of the volume of the elevation is given below:

Here we assume the volume of the elevation be x

As we know that

V¹ ÷ T¹ = V² ÷ T²

Here

V^1 = 1500

T^1 = 290

V^2 = x

T^2 = 210

Now place these values to the above formula

So,

1500 ÷ 290 = x ÷ 210

x = 1086.2 L

7 0

3 years ago