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Serga [27]
3 years ago
5

Metals lose electrons under certain conditions to attain a noble gas electron configuration. How many electrons must be lost by

the element Mg ? Mg? Which noble gas electron configuration is attained in this process? A. argon B. radon C. xenon D. helium E. neon F. krypton
Chemistry
1 answer:
viva [34]3 years ago
5 0

Answer:

2 electrons

E. neon

Explanation:

Metals lose electrons under certain conditions to attain a noble gas electron configuration. Magnesium has 12 electrons and its electron configuration is

1s² 2s² 2p6⁶ 3s²

When magnesium loses 2 electrons, it acquires the electron configuration of neon (10 electrons).

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What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH)<br> 3?
S_A_V [24]

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>

<em />

<em>Molar mass Fe(OH)3 and oxygen:</em>

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
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4 0
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Read 2 more answers
Can anyone solve this?
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