We will see that f'(x) > 0, which means that f(x) is an increasing function.
<h3>
How to prove that the function is increasing?</h3>
For any function f(x), if f'(x) > 0, then f(x) is increasing for any value of x.
Here we have the cubic function:
f(x) = x³ + 4x
If we differentiate this, we get:
f'(x) = df(x)/dx = 3x² + 4.
And notice that x² is always positive, then f'(x) > 0, which means that f(x) is an increasing function.
If you want to learn more about cubic functions:
brainly.com/question/20896994
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Answer:
0.675
Step-by-step explanation:
given that Ted is taking a true-false test. He has a 90% chance of identifying the correct answer to each question. Unfortunately, there is a 25% chance that he will circle the opposite of his intended answer.
For Ted circling the correct answer to any particular question on this test,
first he has to identify the correct answer and then round the correct answer.
Probability for Ted circles the correct answer to any particular question on this test
= Prob for idenfitying correct answer and rounding correct answer
= P(identify correct answer)*P(rounds of correct answer)
= 0.90 ( 1-0.25)
= 0.675
Answer:
F. 5mi/1h
Step-by-step explanation:
It is multiplying 5, the slope, or constant rate of change would be 5.
Step-by-step explanation:
sec(90-A) . Sin A = cot (90-A) . tan(90-A)
cosec X sinA = tanA X cotA
1/sinA X sinA = tanA X 1/tanA
1=1
Hence proved