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kari74 [83]
3 years ago
11

An atom of gold has a mass of 3.271 x 10^-22g. how many atoms of gold are in 5.00g of gold?

Chemistry
2 answers:
Lostsunrise [7]3 years ago
5 0

Answer:

number of gold atoms = 1.528X10^{22}

Explanation:

The mass of one atom of gold is given to be = 3.271X10^{-22}

The mass of gold is given to be = 5.00g

In order to determine the number of atoms present in the 5 g of gold, we will divide the mass of the gold with the mass of each atom of the gold.

the number of atoms = \frac{massofgold}{massofatom}=\frac{5}{3.271X10^{-22}} =1.528X10^{22}

Thus number of gold atoms = 1.528X10^{22}

ra1l [238]3 years ago
4 0
5.00g Au x(1 atom Au/3.271x10^-22 g) = 1.52858x10^22 atoms
Since one of your given terms has only 3 significant figures (5.00g), your answer should only have 3 sig figs showing: 1.53x10^22 atoms Au

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H A and H B are both weak acids in water, and HA is a stronger acid than HB. Which of the following statements is correct? Selec
lubasha [3.4K]

Answer:

B is a stronger base than A^-, which is a stronger base than H2O, which is a stronger base than CI^-

Explanation:

The general equation for each acid is:

HA(aq) + H2O(ac) ⇄ H3O+(aq) + A-(aq)

HB(aq) + H2O(ac) ⇄ H3O+(aq) + B-(aq)

When these acids dissociate into its ions in water they lose a proton (H+), so they are proton donors (acids) and H2O is the proton acceptor (base). This reaction produces a conjugate acid and a conjugate base.

Conjugate base is what remains of the acid molecule after it loses a proton:

HA = acid         A- Conjugate base

HB = acid         B- Conjugate base

A conjugate acid is formed when the proton is transferred to the base

H2O = base                H3O+ = Conjugate acid

The stronger acid will produce a weaker base. According to this, if HA is a stronger acid than HB, A- would be the weaker base (B- is the stronger base).

Compared with water, A- and B- are stronger bases because when they compete for a proton they have much greater affinity for H+ than water does and the equilibrium position will lie far to the left. (HA and HB are weak acids)

Finally Cl- is the weakest base because it comes after dissociation of HCl which is a strong acid

HCl(aq) + H2O → H3O+(aq) + Cl-(aq)

Note there is no double arrows, equilibrium lies far to the right. A strong acid yields a weak conjugate base it means one that has a low affinity for a proton.

4 0
3 years ago
Vitamin c is known chemically by the name ascorbic acid determine the empirical formula of ascorbic acid if it is composed of 40
kow [346]

Answer:

=C_3H_4O_3

Explanation:

When percentage composition is given, and asked for the empirical formula, it is simplest to  assume 100 g of material. Thus,

Mass C = 40.92 g.  Moles C = 40.92 g x 1 mole/12 g = 3.41 moles C

Mass H = 4.58 g.  Moles H = 4.58 g x 1 mole/1.0 g = 4.58 moles H

Mass O = 54.50 g.  Moles O = 54.50 g x 1 mole/16 g = 3.41 moles O

Now, we want to get the moles into whole numbers, so we begin by dividing all by the smallest, i.e. divide all values by 3.41.

Moles C = 3.41/3.41 = 1

Moles H = 4.58/3.41 = 1.34

Moles O = 3.41/3.41 = 1

Now, in order to get 1.34 to be a whole number we multiply it (and all others) by 3

Moles C = 1x3 = 3

Moles H = 1.34x3 = 4

Moles O = 1x3 = 3

Empirical Formula =C_3H_4O_3

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Ilia_Sergeevich [38]
Http://www.chem4kids.com/files/elem_pertable.html this should help.
4 0
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