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kari74 [83]
3 years ago
11

An atom of gold has a mass of 3.271 x 10^-22g. how many atoms of gold are in 5.00g of gold?

Chemistry
2 answers:
Lostsunrise [7]3 years ago
5 0

Answer:

number of gold atoms = 1.528X10^{22}

Explanation:

The mass of one atom of gold is given to be = 3.271X10^{-22}

The mass of gold is given to be = 5.00g

In order to determine the number of atoms present in the 5 g of gold, we will divide the mass of the gold with the mass of each atom of the gold.

the number of atoms = \frac{massofgold}{massofatom}=\frac{5}{3.271X10^{-22}} =1.528X10^{22}

Thus number of gold atoms = 1.528X10^{22}

ra1l [238]3 years ago
4 0
5.00g Au x(1 atom Au/3.271x10^-22 g) = 1.52858x10^22 atoms
Since one of your given terms has only 3 significant figures (5.00g), your answer should only have 3 sig figs showing: 1.53x10^22 atoms Au

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The ionization energies of Calcium are (in KJ/mol): 1st: 589.8 2nd: 1145.4 3rd: 4912.4
defon

Answer:

See whole explanation to understand

Explanation:

the reason why there is such a large jump from 2nd to 3rd ionization energy for calcium is because to remove the third electron, a larger amount of energy is required, since the shell is closer to the nucleus, and higher attraction exists between them. This is why the second ionization energy is 1125.4 and then the third IE is 4912.4 which is a very big difference. It's all about the elections and energy!!

8 0
3 years ago
Read 2 more answers
Isotope Atomic Mass (amu) Percent Abundance
exis [7]

Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

Atomic mass of Si-28 = 27.98 amu

Percent abundance of Si-29 = 4.70%

Atomic mass of  Si-29 = 28.98 amu

Percent abundance of Si-30 = 3.09%

Atomic mass of  Si-30 = 29.97 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100

Average atomic mass =  2580.04 +136.21+92.61 / 100

Average atomic mass = 2808.86 / 100

Average atomic mass  = 28.08amu.

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

7 0
3 years ago
Read 2 more answers
To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3
Brrunno [24]

Answer:

1.87x10⁻³ M SO₄²⁻

Explanation:

The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:

SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)

<em>Where 1 mole of  SO₄²⁻ reacts per mole of Ba²⁺</em>

<em />

To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.

Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).

<em>Moles Ba²⁺:</em>

7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

<em>Molarity SO₄²⁻:</em>

As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:

1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =

<h3> 1.87x10⁻³ M SO₄²⁻</h3>
8 0
3 years ago
Why is the R group in an amino acid important
Alexeev081 [22]
Bc it’s the only group that distinguishes amino acids from one another’s
6 0
3 years ago
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Does the Ba(OH)2 solution contain ions?
LUCKY_DIMON [66]
Yes. It does contain Ions. 
4 0
3 years ago
Read 2 more answers
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