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3 years ago

The children from a football club are put into rows in the sports hall

Mathematics

1 answer:

Nastasia [14]3 years ago

7 0

I think it’s 38
If you divide 38 by 12 and 9 there’s 2 left

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PLEASE HELP

iris [78.8K]

Answer:

1) 32

2) x=9

4) 36

Step-by-step explanation:

6 0

3 years ago

Need help with 7,8,11,12 and the summary

LenKa [72]

Answer:

1) 2

2) 4

11) 3.88

12) 0.01

3 0

3 years ago

Which of the following is an equation of the line through (2,3) and (-1, -12)?

SSSSS [86.1K]

Answer:

C (y=5x-7)

Step-by-step explanation:

First, you find the slope between the 2 points which is 5, then you use one of the points to form an equation.

You then find it's y=5x-7.

8 0

3 years ago

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$

and we found the distance PQ and QA

; $d_{PQ}=\sqrt{125}$ , $d_{QA}=12$

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0

3 years ago

Assume that 33.4% of people have sleepwalked. Assume that in a random sample of 1459 adults, 526 have sleepwalked.

lutik1710 [3]

Answer:

Step-by-step explanation:

Given that 33.4% of people have sleepwalked.

Sample size n =1459

Sample favourable persons = 526

Sample proportion p = $\frac{526}{1459} \\=0.361$

Sample proportion p is normal for large samples with mean = 0.334 and

std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.334(1-0.334)}{1459} } \\=0.0123$

a) P(526 or more of the 1459 adults have sleepwalked.)

$=P(p\geq 0.361)\\=P(Z\geq \frac{0.361-0.334}{0.0123} \\=P(Z\geq 2.20)\\=0.5-0.4861\\=0.0139$

b) Yes, because hardly 1.4% is the probability

c) 33.4 is very less compared to the average. Either sample should be improved representing the population or population mean should be increased accordingly.

7 0

3 years ago