115:2 should be the correct answer in reduced form.
Answer:
a
Step-by-step explanation:
so the 2 in front means stretch 0f 2 the -3 in the parenthaesis means right 3 and the 1 means up 1
If
then complex number
is a root of cubic polynomial.
If polynomial has real coefficients, then conjugated
is also a root of polynomial.
Then the polynomial will be of a form
![p(x)=(x-(3-2i))(x-(3+2i))(x-a).](https://tex.z-dn.net/?f=p%28x%29%3D%28x-%283-2i%29%29%28x-%283%2B2i%29%29%28x-a%29.)
Since
then
![-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.](https://tex.z-dn.net/?f=-52%3D%280-%283-2i%29%29%280-%283%2B2i%29%29%280-a%29%2C%5C%5C%20%5C%5C-52%3D%282i-3%29%283%2B2i%29a%2C%5C%5C%20%5C%5C-52%3D%284i%5E2-9%29a%2C%5C%5C%20%5C%5C-52%3D%28-4-9%29a%2C%5C%5C%20%5C%5C-13a%3D-52%2C%5C%5C%20%5C%5Ca%3D4.)
Therefore,
![p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.](https://tex.z-dn.net/?f=p%28x%29%3D%28x-%283-2i%29%29%28x-%283%2B2i%29%29%28x-4%29%2C%5C%5C%20%5C%5Cp%28x%29%3D%28x%5E2-6x%2B13%29%28x-4%29%2C%5C%5C%20%5C%5Cp%28x%29%3Dx%5E3-10x%5E2%2B37x-52.)
Step-by-step explanation:
![1 \div 100th](https://tex.z-dn.net/?f=1%20%5Cdiv%20100th)