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melomori [17]
3 years ago
7

Which postulate or theorem proves that these two triangles are congruent?

Mathematics
2 answers:
swat323 years ago
4 0

ANSWER

postulate or theorem proves that these two triangles are congruent is option (C)

i.e   AAS Congruence Theorem

Reason

AAS Congruence Theorem

In this theorem two angle and one sides of the two triangle are equal.

In ΔMNR and ΔQNP

∠MNR =∠ QNP

( Vertically opposite angle property )

∠RMN = ∠QPN

(Corresponding angle property)

RN = NQ

( As given in the diagram )

therefore

ΔMNR≅ Δ QNP

these triangle are congurent by the  AAS Congruence Theorem.

Hence proved






kotegsom [21]3 years ago
4 0

Answer:

C) AAS Congruence Theorem

Step-by-step explanation:

The Angle Angle Side postulate (often abbreviated as AAS) states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.

In this case the congruent angles are: M with P (shown in the figure) and N, which is equal in both triangles because two opposite angles are formed in the intersection of segments MP with RQ.

The congruent non-included sides are RN and NQ (shown in the figure).

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A tabletop in the shape of a trapezoid has an area of 6,550 square centimeters. It's longer base measures 115 centimeters, and s
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3 years ago
1. Convert 60° to radians.
hram777 [196]

Answer:

60° = \frac{\pi }{3} radians

Step-by-step explanation:

To convert from degrees to radians

radian measure = degree measure × \frac{\pi }{180}

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5 0
3 years ago
According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x^5
nata0808 [166]

Answer:

The correct option is A.

Step-by-step explanation:

The question is:

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 – 2x4 + 9x3 – x2 + 12?

A).f(x) = 3x5 – 2x4 – 9x3 + x2 – 12

B).f(x) = 3x6 – 2x5 + 9x4 – x3 + 12x

C).f(x) = 12x5 – 2x4 + 9x3 – x2 + 3

D).f(x) = 12x5 – 8x4 + 36x3 – 4x2 + 48

Solution:

The function given to us is:

3x5 – 2x4 + 9x3 – x2 + 12

Find the factors of 12 and consider it as 'p'

The factors of 12 are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q'

The factors of 3 are:

q = +/- 1 , +/- 3

We know that we write rational terms in p/q form.

Therefore the Rational roots are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Now we will solve the first function given in part A.

f(x) = 3x^5 – 2x^4 - 9x^3 + x^2 - 12

Again find the factors of 12 and consider it as 'p'

The factors are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q' .

q = +/- 1 , +/- 3

Rational root are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Therefore the rational roots of the given function matches the rational roots of the given equation.

Hence the correct option is A

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