Answer:
By preventing the government from taking property without fair payment.
Explanation:
Answer 1
Please mark me as brilliant and thank you
Answer:
18.89cm
Explanation:
As we know that the person is standing 5m in front of the camera
The focal length of the lens =50cm
f=50 cm
By Lens formula we have:
By the formula of magnification
The height of the image formed is 18.89cm.
The
two precipitation peaks in Mbandaka during March to April and September to
November is due to the intertropical convergence zone.
Intertropical
convergence zone is a narrow zone located near the equator. It is where the
northern and southern air masses intersect which results to low atmospheric
pressure. Due to the intertropical convergence zone’s meeting of air masses,
often times the air pressure are lower which will results to colder air, or
even rainfall during the period of March to April, and most especially
September to November in Mbandaka.
<span>Since
Mbandaka is located at the cented of Tumba-Ngiri-Maindombe area, which is named
as a Wetland of International importance, there is really a bigger chance that
this place experience above 60mm precipitation in a year, temperatures averaging
from 23 – 26 degrees Celsius.</span>
Answer:
a) t = 0.90 s, b) t = 0.815 s, c) t = 0.90 s, d) x = 3.6 m, e) t = 0.639 s
Explanation:
all these exercises are about kinematics
a) The body is released from rest,
y = y₀ + v₀ t - ½ g t²
in this case when reaching the ground y = 0 and its initial velocity is vo = 0
0 = y₀ + 0 - ½ g t²
t² = 2 y₀ / g
t² = 2 4 /9.81
t² = 0.815
t = √0.815
t = 0.90 s
b) It is thrown upwards at v₀ = 4 m / s
y = y₀ + v₀ t - ½ g t²
in this case the initial and final height is the same
y = y₀ = 0
0 = v₀ t -1/2 g t²
t = 2 v₀ / g
t = 2 4 /9.81
t = 0.815 s
c) the ball is at y₀ = 4 m and its initial velocity is horizontal v₀ = 4 m / s
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
t² = 2 i / g
t² = 2 4 / 9.81
t² = 0.815
t = 0.90 s
d) the horizontal distance traveled is
x = v₀ₓ t
x = 4 0.90
x = 3.6 m
e) We can calculate the time to fall from I = 2 m
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
t² = 2 y₀i / g
t² = 2 2 /9.81
t² = 0.4077
t = 0.639 s
Therefore, when making measurements, you should find readings around this value.
Answer:
Gas Bubbles Appear,
Formation of a Precipitate,
Color Change,
Temperature Change,
Production of Light,
Volume Change,
Change in Smell or Taste
Explanation:
