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lesya692 [45]
3 years ago
8

Consider a group of kk people. Assume that each person's birthday is drawn uniformly at random from the 365 possibilities. (And

ignore leap years.) What is the smallest value of kk such that the expected number of pairs of distinct people with the same birthday is at least one?
Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

366

Step-by-step explanation:

Since there are 365 possible slots for people to have their birthday on, the worst case happens when all 365 people have different birthday. This means the 366th person would have their birthday falls on any of other’s birthday. Hence, kk must be at least 366.

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4 0
3 years ago
At the bank, Derek made 7 withdrawals, each in the same amount. His brother, John, made 5 withdrawls, each in the same amount. E
spayn [35]

At the bank, Derek made 7 withdrawals, each in the same amount. His brother, John, made 5 withdrawls, each in the same amount.

Let x be  the amount of one of Derek's withdrawals

Each of John's withdrawals was $5 more than each withdrawal that Derek made.

x + 5 is t the amount of one of John's withdrawals

Derek made 7 withdrawals

So amount withdraw 7 times = 7x

John made 5 withdrawals

So amount withdraw 5 times = 5(x+5)

Both Derek and John withdrew the same amount of money in the end

(A) 7x = 5(x+5)

(B) Solve for x

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(C) check your solution

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6 0
3 years ago
which table represents the function y = 4x - 3? Input x 0 1 2 Output y -3 -2 -1 Input x 0 1 2 Output y -3 1 5 Input x 0 1 2 Outp
julsineya [31]
<span>Input x 0 1 2 Output y -3 1 5

Your second option here works perfectly for it. If you plug in each input it equals the outputs in order. </span>
5 0
4 years ago
Read 2 more answers
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