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STALIN [3.7K]
3 years ago
8

NiO is to be reduced to nickel metal in an industrial process by use of the reaction:NiO(s) + CO(g) <-----> Ni(s) + CO2(g)

At 1600K the equilibrium constant for the reaction is kp = 6.0 x 10^2. If a CO pressure of 150 torr is to be employed in the furnace and total pressure never exceeds 760 torr, will reduction occur?
Chemistry
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

The reaction will occur, in the forward direction, and NiO will be reduced to Ni

Explanation:

Step 1: Data given

Kp = 6.0 * 10²

Pressure of CO = 150 torr

Total pressure never exceeds 760 torr

Step 2: The balanced equation:

NiO(s) + CO(g) ⇆ Ni(s) + CO2(g)

Step 3: Calculate P(CO) and P(CO2)

For this equilibrium, the expression for Kp is:

Kp = P(CO2)/P(CO) = 6.0*10^2

(NiO and Ni are solids so do not change anything to the Kp

⇒ with P(CO) = 150 torr

⇒ P(CO) = 760 - 150 = 610 torr

Step 4: Calculate the reaction quotient

Q = 610/150 = 4.1

Q<<< Kp

There are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

This means the reaction will proceed in the forward direction, and NiO will be reduced to Ni.

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You have 400 kg of a radioactive substance with a short half-life of 1000 years. how much will be left after these times?
Amiraneli [1.4K]
Half-life of a radioactive substance is the time required to reduce the amount of substance to half of its initial amount. 

In present case, half-life is material is given as 1000 years and initial amount of material is given as 400 kg
 
Answer 1) Since, half-life of radio-active substance is 1000 years, therefore after 1st half life, amount of the material will be left to half the initial amount. Hence, amount of substance left after 1000 years = 400/2 = 200 kg.

Answer 2) For 2000 years, radioactive material has crossed 2 times the half life. Therefore ,  amount of the material will be left to 1/4 the initial amount. Hence, amount of substance left after 2000 years = 400/4 = 100 kg.

Answer 3) 
 For 4000 years, radioactive material has crossed 4 times the half life. Therefore , amount of the material will be left to 1/16 the initial amount. Hence, amount of substance left after 4000 years = 400/16 = 25 kg.
8 0
3 years ago
When aqueous solutions of Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the mass of PbSO4 formed when 1.25 L of 0
neonofarm [45]

Answer:

The mass of PbSO4 formed 15.163 gram

Explanation:

mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625

mole of Na₂SO₄ = 2 x 0.025 = 0.05

                                      Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃

( Mole/Stoichiometry )    \frac{0.0625}{1}           \frac{0.05}{1}

                                     = 0.0625     = 0.05

From  (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.

Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄

                                            = 0.05 x 303.26 g

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7 0
3 years ago
Which of the data sets qualitative data?
Kaylis [27]

Answer:

Uh, the second one?

Explanation:

Try to restate the question please.

3 0
3 years ago
Read 2 more answers
Whoever awser correct I will give you Brainly
vivado [14]

Answer:

Option A.

2Na + 2H2O —> 2NaOH + H2

Explanation:

To know which option is correct, we shall do a head count of the number of atoms present on both side to see which of them is balanced. This is illustrated below below:

For Option A:

2Na + 2H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

4 H >>>>>>>>>>>> 4 H

2 O >>>>>>>>>>>> 2 O

Thus, the above equation is balanced.

For Option B:

2Na + 2H2O —> NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 3 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

For Option C:

2Na + H2O —> 2NaOH + H2

Reactant >>>>>>> Product

2 Na >>>>>>>>>>> 2 Na

2 H >>>>>>>>>>>> 4 H

1 O >>>>>>>>>>>> 2 O

Thus, the above equation is not balanced.

For Option D:

Na + 2H2O —> NaOH + 2H2

Reactant >>>>>>> Product

1 Na >>>>>>>>>>> 1 Na

4 H >>>>>>>>>>>> 5 H

2 O >>>>>>>>>>>> 1 O

Thus, the above equation is not balanced.

From the illustrations made above, only option A is balanced.

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