Pressure has little effect on the solubility of liquids and solids because they are almost incompressible True.
Liquids and solids show little change in solubility with changes in pressure. As expected, gases increase in solubility with increasing pressure. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the surface of the solution.
External pressure has little effect on liquid and solid solubility. In contrast, the solubility of a gas increases as the partial pressure of the gas above the solution increases.
Solubility is a measure of the concentration of dissolved gas particles in a liquid and is a function of gas pressure. Increasing the gas pressure increases the number of collisions and increases the solubility, and decreasing the pressure decreases the solubility.
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Answer:
Explanation:
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This is an oxidation reaction. The balanced equation is as follows:
6H₂O + N₂ → 2NO₃⁻+ 12H⁺ + 6e⁻
Rules to balance redox reaction in acidic medium
- Write the given equation in ionic form
- Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
- Break the equation into two halfs
- Balance the half equations
A. Balance all other atoms except Oxygen and hydrogen
B. Balance oxygen by adding H2O to the side deficient in oxygen
C. Balance hydrogen by adding H+ ions
D. Balance charge by adding electrons
5. Add the two half such that electrons gets cancelled
Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.
N₂(g) → NO₃⁻(aq)
N₂ → 2NO₃⁻
6H₂O + N₂ → 2NO₃⁻
6H₂O + N₂ → 2NO₃⁻+ 12H⁺
- balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.
6H₂O + N₂ → 2NO₃⁻+ 12H⁺ + 6e⁻
Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.
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Energy is supplied to aluminium to raise the temperature of aluminium.
we can use the following equation to calculate the mass of aluminium
H = mcΔt
H - heat energy supplied
m - mass of material
c - specific heat capacity of aluminium
Δt - change in temperature - 35 °C - 15 °C = 20 °C
substituting the values in the equation
216 J = m x 0.90 J°C⁻¹g⁻¹ x 20 °C
m = 12 g
mass of aluminium is 12 g