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ser-zykov [4K]
3 years ago
15

A lightning bolt may carry a current of 1.00 104 A for a short time. What is the resulting magnetic field 160 m from the bolt? S

uppose that the bolt extends far above and below the point of observation. μT
Physics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

Result magnetic field=

1.25*10^-^5T

Explanation:

We are given:

I = 1.00*10^4A

r = 160m

Let us say the lightning bolt is a long straight conductor.

Therefore we will use the formula:

B = Uo•I / 2πr

Substituting figures in the equation, we have:

B = [(4π*10^-^7 T•m/A)(1.00*10^4)] / (2π * 160);

= 1.25 * 10^-^5 T;

Therefore, the result magnetic field at 160m = 1.25 * 10^-^5

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Feliz [49]
<span>6.7 x 10-11....Have a good day with a big fat A+

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3 0
3 years ago
Read 2 more answers
A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how
Nata [24]

Answer:

C. 72

Explanation:

Transformer: A transformer is an electromagnetic device that uses the property of mutual inductance to change the voltage of alternating supply.

In a ideal transformer,

Vs/Vp = Ns/Np ............................................. Equation 1

Where Vp = primary voltage, Vs = secondary voltage, Ns = Secondary turn, Np = primary turn.

Making Ns the subject of the equation,

Ns =(Vs/Vp)Np .......................................... Equation 2

Given: Vs = 24 V, Vp = 115 V, Np = 345.

Substitute into equation 2

Ns = (24/115)345

Ns = 72 turns.

Thus the number of turns in the secondary = 72 turns.

The right option is C. 72

4 0
3 years ago
A computer is purchased for $2816 and depreciates at a constant rate to $0 in 8 years. Find a formula for the value, V , of the
marusya05 [52]

Answer:

  • The formula its f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816
  • After 5 years, the computer value its $ 1056

Explanation:

<h3>Obtaining the formula</h3>

We wish to find a formula that

  • Starts at 2816. f(0 \ years) \ = \ \$ \ 2816
  • Reach 0 at 8 years. f( 8 \ years) \ = \ \$ \ 0
  • Depreciates at a constant rate. m

We can cover all this requisites with a straight-line equation. (an straigh-line its the only curve that has a constant rate of change) :

f(t) \ = \ m\ t \ + \ b,

where m its the slope of the line and b give the place where the line intercepts the <em>y</em> axis.

So, we can use this formula with the data from our problem. For the first condition:

f ( 0 \ years ) = m \ (0 \ years) + b = \$ \ 2816

b = \$ \ 2816

So, b = $ 2816.

Now, for the second condition:

f ( 8 \ years ) = m \ (8 \ years) + \$ \ 2816 = \$ \ 0

m \ (8 \ years) = \ - \$ \ 2816

m = \frac{\ - \$ \ 2816}{8 \ years}

m = \frac{\ - \$ \ 2816}{8 \ years}

m = \ - \ 352 \frac{\$ }{years}

So, our formula, finally, its:

f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816

<h3>After 5 years</h3>

Now, we just use <em>t = 5 years</em> in our formula

f(5 \ years) \ = \ - \ 352 \ \frac{\$ }{years} \ 5 \ years \ + \ \$ \ 2816

f(5 \ years) \ = \ - \$ \ 1760 + \ \$ \ 2816

f(5 \ years) \ = $ \ 1056

4 0
4 years ago
It took 500 N of force to push a car 4 meters. How much work was done?
djverab [1.8K]

Answer:

200 J

Explanation:

W = F S

W= 500 x 4

W = 2000

6 0
3 years ago
You are carrying a 7.0-kg bag of groceries as you walk at constant velocity along the sidewalk. You walk a distance of 82 meters
Alenkasestr [34]

Answer:

the work againts gravity is zero (0)

Explanation:

This is because the work is always done, by a force that acts parallel in the direction of the displacement of the body.

In this case, the gravity and the weight of the bag is not acting in the direction of the displacement, therefore there is no work done.

6 0
3 years ago
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