Question

A lightning bolt may carry a current of 1.00 104 A for a short time. What is the resulting magnetic field 160 m from the bolt? Suppose that the bolt extends far above and below the point of observation. μT

Answer 1

Answer:

Result magnetic field=

$1.25*10^-^5T$

Explanation:

We are given:

$I = 1.00*10^4A$

r = 160m

Let us say the lightning bolt is a long straight conductor.

Therefore we will use the formula:

B = Uo•I / 2πr

Substituting figures in the equation, we have:

$B = [(4π*10^-^7 T•m/A)(1.00*10^4)] / (2π * 160)$;

$= 1.25 * 10^-^5 T$;

$Therefore, the result magnetic field at 160m = 1.25 * 10^-^5$