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Nezavi [6.7K]
3 years ago
14

Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal

tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.
Physics
2 answers:
taurus [48]3 years ago
6 0

Answer:

c) Tungsten is ductile, has a high melting point, and is electrically conductive.

Explanation:

i took the test

Anastaziya [24]3 years ago
5 0

The most important characteristics that are exhibited by metals are-

1- Metals are ductile

2-Most metals are conductive in nature.

3-Most metals are malleable.

4- Metals have strong inter molecular force of attraction between the.

5-Metals have luster.

6-Metals are sonorous.

Here we are given Tungsten filament.

Tungsten is  a metal.So it must be conductive and as well as ductile in nature.

The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.

The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.

Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.



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When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the
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8 0
3 years ago
An 80.0-kg man jumps from a height of 2.50 m onto a platform mounted on springs. As the springs compress, he pushes the platform
frosja888 [35]

Answer:

6.16 m/s

0.0105 m

Explanation:

Let the ground 0 for potential reference be at where the spring is compress 0.24 m. The the man would jump from a height h = 2.5 + 0.24 = 2.74 m from it. We can apply the law of energy conservation knowing that as the man jumps, his potential energy converts to kinetic energy, then finally to elastic energy:

E_p = E_e

mgh = kx^2/2

where m = 80 kg is the man mass, g = 9.81 m/s2 is the gravitational acceleration, h = 2.74 m is the potential distance he travels, k N/m is the spring constant and x = 0.24 is the distance it compresses

80*9.81*2.74 = k0.24^2/2

2150.352 = 0.0288k

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Similarly at the position where it compresses by 0.12 m, it's 0.24 - 0.12 = 0.12 m far from ground 0.

E_p = E_{e2} + E_k + E_{p2}

mgh = kx_2^2 + mv^2/2 + mgh_2

2150.352 = 74665*0.12^2/2 + 80v^2/2 + 80*9.81*0.12

2150.352 = 537.588 + 40v^2 + 94.176

40v^2 = 1518.588

v^2 = 37.9647

v = \sqrt{37.9647} = 6.16 m/s

When he steps gently, then his gravity force would equal to his spring force

mg = kx_3

x_3 = mg/k = 80*9.81/74665 = 0.0105m

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