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Nezavi [6.7K]
3 years ago
14

Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal

tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.
Physics
2 answers:
taurus [48]3 years ago
6 0

Answer:

c) Tungsten is ductile, has a high melting point, and is electrically conductive.

Explanation:

i took the test

Anastaziya [24]3 years ago
5 0

The most important characteristics that are exhibited by metals are-

1- Metals are ductile

2-Most metals are conductive in nature.

3-Most metals are malleable.

4- Metals have strong inter molecular force of attraction between the.

5-Metals have luster.

6-Metals are sonorous.

Here we are given Tungsten filament.

Tungsten is  a metal.So it must be conductive and as well as ductile in nature.

The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.

The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.

Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.



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2.72 N

Explanation:

Step 1:

From the basic formula in electrostatics

F = E * q

where F = Force due to charges

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Step 2:

From the given question

q= 8.5*10^{-6} C

E = 3.2 * 10^{5} N/C

F = 8.5 * 10^{-6} * 3.2 * 10^{5} = 2.72 N

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for the compressor in our problem, the intensity of current is I=66.1 A, while the time is \Delta t= 0.388 s, so the amount of charge that crosses a certain point of the circuit during this time is
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Answer:

Explanation:

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Answer:

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Jason places his economics book (3 kg) on a level table. He then puts his calculus book (5 kg) on top of the economics book, the
lilavasa [31]

Nothing is accelerating ... it's not even moving. Everything is just sitting there. 
That right there tells you that the forces are balanced wherever two things meet,
otherwise something would be accelerating.

At each level where two things meet, there are 2 forces:

-- The gravitational force ... the weight of everything above that place,
and
-- The upward force, exerted by everything below that place. 

Here is the stack:
_____________
| Physics ... 2kg |      weight = M G = 2 x 9.8 = 19.6 newtons
---------------------
|Calculus ..5 kg |      weight = M G = 5 x 9.8 = 49 newtons
---------------------
|Econ . . . .3 Kg |      weight = M G = 3 x 9.8 = 29.4 newtons
==================
-------- (Table) ----------
/                                  \

a).  Surface where the table meets the Economics book.
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Upward force exerted on the Econ book by the table = 98 newtons.

b). Surface where the Econ book meets the Calculus book.
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c).  Surface where the Calculus book meets the Physics book.
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Force exerted on the Physics book by the Calc book = 19.6 newtons.
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