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schepotkina [342]
2 years ago
8

The pigment cyanidin aglycone is one of the anthocyanin molecules that gives red cabbage (Brassica oleracea var. capitata f. rub

ra) its characteristic red coloration. Many young chemists have used this “red cabbage indicator” to study acid–base chemistry. Estimate the pH range at which cyanidin aglycone shows a color change. Anth-H Anth- + H+ Ka = 1.3 x10 -7
Chemistry
1 answer:
miskamm [114]2 years ago
8 0

Hey there!

The pH range of a buffer is the pH window where in the uffer resists the changes in pH of the solution upon addition of small amounts of acid or base. Generally, the pH range of a buffer solution is equal to pKa ±1.

for this system :

ka= 1.3*10⁻⁷ , hence

pKa= - log (Ka)

pKa =  - log ( 1.3*10⁻⁷)

pKa = 6.88

Therefore, hence the buffer can be used in pH range of 5.88 to 7.88.


Hope that helps!

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The behavior of light can be modeled as _______.
777dan777 [17]

Answer:

c

Explanation:

4 0
3 years ago
A standard 1.00 kg mass is to be cut from a bar of steel having an equilateral triangular cross section with sides equal to 2.50
Elden [556K]

Answer:

The section of the bar is 2.92 inches.

Explanation:

Mass of the steel cut ,m = 1.00 kg = 1000 g

Volume of the steel bar = V = Area × height

Height of the of the  section of bar = h

Area of  Equilateral triangular = \frac{\sqrt{3}}{4}a^2

a = 2.50 inches

Cross sectional area of the steel mass = A

A=\frac{\sqrt{3}}{4}(2.50 inches)^2=2.71 inches^2

V = 2.71 inches^2\times h

Density of the steel = d =7.70 g/cm^3

1cm^3 = 0.0610237 inches^3

d=\frac{m}{v}

\frac{7.70 g}{0.0610237 inches^3}=\frac{ 1000 g}{2.71 inches^2\times h}

h=\frac{ 1000 g\times 0.0610237 inches^3}{2.71 inches^2\times 7.70 g}

h = 2.92 inches

The section of the bar is 2.92 inches.

3 0
2 years ago
I need help with problem 103 all of the questions.
AfilCa [17]
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balanced

b. Br2 + Al-i = AlBr3 + I2 single rep.

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3Br2 + Al-i = 2AlBr3 + I2 now left Al is unbal. so make 2 there

3Br2 + 2Ali = 2AlBr3 + I2 

Balanced

C. Na + S = Na2S synthesis reaction is not bal. left Na needs 2

2Na + S = Na2S  balanced.

4 0
2 years ago
Calcium has an atomic number of 20. How many electrons does calcium lose when forming an ionic bond with another ion?
oksano4ka [1.4K]
2 electrons. it has electron configuration of 2.8.8.2 hence the last 2 will be lost for it to gain stable.
if you need more explanation on periodic table you can reach me at [email protected]
5 0
3 years ago
Is it always easy to classify research as applied or pure? Explain.
Luda [366]

No..since research can take different format

3 0
3 years ago
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