Answer:
The correct option is: B. Carbon 5 only
Explanation:
Carvone is a naturally-occurring monoterpenoid consisting of a six-membered cyclic ring. <u>The </u><u><em>carbon-5</em></u><u> of this cyclic ring of Carvone is </u><u><em>chiral, </em></u><u>due to which Carvone exhibits </u><u><em>enantiomerism</em></u><u>.</u>
The two <em>enantiomeric forms</em> of Carvone are: R-(–)-carvone, or L-carvone, and S-(+)-carvone, or D-carvone.
<em><u>These two enantiomeric forms differ in the orientation of the substituents on the chiral carbon-5.</u></em>
<u />
<u>Therefore, the correct option is B. Carbon 5 only.</u>
C-12? (6 protons) C-13? (6 protons) C-14? (6 protons)
Granite forms when
magma cools slowly underground. Granite is an intrusive igneous rock.
The answer is letter B. granite is composed mostly of quartz and feldspar with
minor amounts of mica, amphiboles and other minerals.
<u>Answer:</u> The mass of sample A after given time is 99.05 g.
<u>Explanation:</u>
All the radioactive reactions follows first order kinetics.
The equation used to calculate half life for first order kinetics:

We are given:

Putting values in above equation, we get:

Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = 84.2 s
= initial amount of the reactant = 250 g
[A] = amount left after decay process = ?
Putting values in above equation, we get:
![0.011s^{-1}=\frac{2.303}{84.2s}\log\frac{250}{[A]}](https://tex.z-dn.net/?f=0.011s%5E%7B-1%7D%3D%5Cfrac%7B2.303%7D%7B84.2s%7D%5Clog%5Cfrac%7B250%7D%7B%5BA%5D%7D)
![[A]=99.05g](https://tex.z-dn.net/?f=%5BA%5D%3D99.05g)
Hence, the mass of sample A after given time is 99.05 g.