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Marina CMI [18]
3 years ago
14

Under what circumstances will a scientific theory be changed or discarded

Chemistry
2 answers:
VMariaS [17]3 years ago
7 0

If new evidence or observations falsify a scientific theory, the theory will have to be changed to adapt to the new data or just discarded altogether.

Mandarinka [93]3 years ago
6 0

If new evidence or observations falsify a scientific theory, the theory will have to be changed to adapt to the new data or just discarded altogether. yes

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Change the places of 'acts against the motion of an object' and 'causes an object to change speed or direction'
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3 years ago
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cupoosta [38]

its 40

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7 0
3 years ago
Can someone help out pls
Troyanec [42]

Answer:

1. Acids

2. Its molecular arrangement

3. Very acidic

4. Unsaturated

5. Apple juice

Explanation:

1. Acids have pH less than 7

2. Water molecules have a polar arrangement of the oxygen and hydrogen atoms—one side (hydrogen) has a positive electrical charge and the other side (oxygen) had a negative charge.3. Very acidic

4. Unsaturated solutions are solutions in which the amount of dissolved solute is less than the saturation point of the solvent (at that specific temperature gradient).

5. The lower the pH, the more hydrogen molecules.

4 0
2 years ago
Read 2 more answers
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

7 0
3 years ago
Which atom, selenium (Se) or Arsenic (As), has the higher electron affinity and why?
IrinaVladis [17]

Answer:

5. Selenium, because it does not have a stable, half-filled p subshell and adding an electron does not decrease its stability.

Explanation:

Electron affinity is the amount of energy released when an isolated gaseous atom accepts electron to form the corresponding anion.

Selenium:-

The electronic configuration of the element is:-

[Ar]3d^{10}4s^24p^4

Arsenic:-

The electronic configuration of the element is:-

[Ar]3d^{10}4s^24p^3

The 4p orbital in case of arsenic is half filled which makes the element having more stability as compared to selenium.

Thus, selenium has higher electron affinity because adding electron does not decrease the stability as in case of arsenic.

8 0
2 years ago
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