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sergiy2304 [10]
3 years ago
8

When hafnium metal is heated in an atmosphere of chlorine gas, the product of the reaction is found to contain 62.2 percent Hf b

y mass and 37.4 percent Cl by mass. What is the empirical formula for this compound?
Chemistry
1 answer:
Artemon [7]3 years ago
8 0

Answer:

HfCl3

Explanation:

Step 1

Divide the percent by mass of each element by its relative atomic mass

Hf- 62.2/178.5, Cl-37.4/35.5

0.348, 1.054

Step2

Divide through by the lowest ratio

0.348/0.348, 1.054/0.348

1, 3

Therefore the empirical formula is HfCl3

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s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

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Lo cual hace que la expresión de equilibrio se calcule como:

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Y que en términos de la solubilidad molar, s, se resuelve como:

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Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

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¡Saludos!

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