What percentage of the original kinetic energy is convertible to internal energy?

1 answer:

7 0

There would be very less percentage loss<span> of the kinetic energy during </span>the conversion<span> to internal energy, assuming that there is less air in the </span>surroundings<span>. Also, the friction will contribute to the conversion where if it is, the percentage loses is negligible.</span>

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To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

$\beta_{dB} = 10log_{10}\frac{I}{I_0}$

Where,

$\beta_{dB}$ = Sound intensity level in decibels

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So:

$10log_{10}(\frac{32I}{I_0}) = 83$

$10log(\frac{I}{I_0})+10log(32) = 83$

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