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anastassius [24]
3 years ago
15

(Double points) A worker applied 27 newtons to a lever with a length of 4 meters that rotated around a hinge. What was the torqu

e?
Physics
2 answers:
arlik [135]3 years ago
7 0

Answer: Torque T = 108 Nm

Explanation:

Torque or turning effect is the rotational equivalent of linear force, i.e moment of force about a point.

Given that the force is applied perpendicular to the edge (angle 90°)

Torque can be represented by T;

T = FrSin∅ = Fr ( sin90 = 1)

T = force × distance

T = F × r

F = 27N

r = 4m

T = 27N × 4m

T = 108 Nm

faltersainse [42]3 years ago
4 0

Answer:

The torque was 108 N m

Explanation:

Torque is the cross product between the vector position where the force is applied with respect the axis of rotation and the force applied:

\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}

The magnitude is:

\tau =rF\sin \theta

If the force is applied on an extreme of the lever, the hinge is in the other extreme and the applied force is perpendicular to the lever:

r=4m, F=27N, \theta=90 Celcius

So:

\tau=(4m)(27N)\sin (90)=(108Nm)(1)

\tau=108 Nm

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Answer: F = 1235 N

Explanation: Newton's Second Law of Motion describes the effect of mass and net force upon acceleration: F_{net}=m.a

Acceleration is the change of velocity in a period of time: a=\frac{\Delta v}{\Delta t}

Velocity of the car is in km/h. Transforming it in m/s:

v=\frac{47.10^{3}}{36.10^{2}}

v = 13 m/s

At the moment the car decelerates, acceleration is

a=\frac{13}{0.2}

a = 65 m/s²

Then, force will be

F_{net}=19(65)

F_{net} = 1235 N

The horizontal net force the straps of the restraint chair exerted on the child to hold her is 1235 newtons.

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3 years ago
Select the correct answer.
andrew-mc [135]
I think the answer would be C
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Bohr’s model showed that electron orbits had distinct radii.

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You are trying to decide between two new stereo amplifiers. One is rated at 130 W per channel and the other is rated at 200 W pe
NARA [144]

Answer:

The sound level will be 1.870 dB louder.

Explanation:

Given that,

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Power = 200 W

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Using formula of sound level

I_{dB}=10\log(\dfrac{I}{I_{0}})

For one amplifier,

I_{1}=10\log(\dfrac{130}{I_{0}})...(I)

For other amplifier,

I_{2}=10\log(\dfrac{200}{I_{0}})...(II)

For difference in dB levels

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}})-10\log(\dfrac{130}{I_{0}})

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}}\times\dfrac{I_{0}}{130})

I_{2}-I_{1}=10\log(\dfrac{200}{130})

I_{2}-I_{1}=1.870\ dB

Hence, The sound level will be 1.870 dB louder.

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Two linear polarizing filters are placed one behind the other so that their transmission directions form an angle of 45 ° . A be
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The transmitted intensity will be the quarter of the incident intensity of light, (I = 0.25 I₀), when two linear polarizing filters are placed one behind the other forming the angle of 45°.

<u>Explanation:</u>

Polarizers are used for constraining the direction of propagation of light waves.  So depending upon the angle of polarizer, the transmitted rays will follow that angle only and the remaining lights waves at different angles will be reflected back. So basically it works like a filter or optical filters.

So, the transmitted intensity will be less compared to the original intensity of light as the beam will get confined in a particular angle.

The relation between transmitted intensity and incident intensity is given by Malus's law.

I = { \frac {I_{0}} {2}} \times cos^{2} \alpha

Here, I is the transmitted intensity, I₀ is the incident intensity and α is the angle of the polarizer.

In the present case, two polarizers are used with same angle, so the first one termed as polarizer, while the second one will be termed as analyzer. The angle which is used to polarize the intensity of the incident beam is the angle of 45°.

Then, according to Malus's law,

I = I₀ cos² 45 = (I₀/2)×(1/√2)² = I₀/4 = 0.25\ I_0

So, the transmitted intensity will be the quarter of the incident intensity of light, (I = 0.25 I₀), when two linear polarizing filters are placed one behind the other forming the angle of 45°.

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