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allsm [11]
3 years ago
5

HELLLLLLLLLLLLLLLLP QUICKKKKKKKK PLZZZZZ

Physics
2 answers:
Orlov [11]3 years ago
4 0
D- a scientific inquiry involves all of those procedures. <span />
Alik [6]3 years ago
3 0
It would be D since they all follow the scientific method

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Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h
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Disagree.
Fluoresce objects will only glow when put under actual Ultraviolet light. This is due to the molecules becoming excited by the ultraviolet radiation.


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3 years ago
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Which of the following statements is accurate? A. Sound waves passing through the air will do so as transverse waves, which vibr
egoroff_w [7]

The answer is, C. the wavelength is measured in parallel to the direction of the wave, at any point, under the same repetition for any type of wave.

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3 years ago
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A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be ove
jonny [76]

We must remember that the total net force equation at constant velocity is:

<span>F – Ff = 0</span>

of

F - µN = 0

Using Newton's 2nd Law of Motion:<span>

F = m a 

<span>Where,

F = net force acting on the body 
m = mass of the body 
a = acceleration of the body 

Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to 

F = net Force = 0 

Therefore, 

F - µN = 0 

where 

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4 0
3 years ago
If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr, what will
evablogger [386]

Answer:

(a) 49.0 mm

Explanation:

#First we need to calculate the height of the mercury arm:

Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:

P_g_a_s=P_a_t_m+P_h\\  

The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

P_g_a_s=P_a_t_m+P_h\\797.3=P_a_t_m+(136.4mm-103.8mm)\\P_a_t_m=764.7mm\\\\h_t_o_t_a_l=136.4mm+103.8mm=240.2mm\\\\P_g_a_s=P_a_t_m+\bigtriangleup h\\\bigtriangleup h=P_g_a_s-P_a_t_m\\\\\bigtriangleup h=715.7mm-764.7mm\\=-49mm

Hence the height of the mercury in the arm is 49.00mm

4 0
3 years ago
Can someone show me the work of this
Alik [6]

Answer:

use symbollab it will help u

Explanation:

7 0
3 years ago
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