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allsm [11]
3 years ago
5

HELLLLLLLLLLLLLLLLP QUICKKKKKKKK PLZZZZZ

Physics
2 answers:
Orlov [11]3 years ago
4 0
D- a scientific inquiry involves all of those procedures. <span />
Alik [6]3 years ago
3 0
It would be D since they all follow the scientific method

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Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 30.0 mph and half the
salantis [7]

Answer:

Explanation:

Given

Distance to grandmother's house=100 mi

it is given that during return trip Julie spend equal time driving with speed 30 mph and 70 mph

Let Julie travel x mi with 30 mph and 100-x with 70 mph

\frac{x}{30}=\frac{100-x}{70}

x=30 mi

Therefore

Julie's Average speed on the way to Grandmother's house=\frac{100}{\frac{50}{30}+\frac{50}{70}}

=42 mph

On return trip

=\frac{100}{2\frac{30}{30}}=50 mph

6 0
4 years ago
The frequency of a certain sound is 440 Mz. What is the wavelength of this sound when the temperature of the air is (a) 20°C; (b
Serggg [28]

Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ

:

λ

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v

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λ

=

340

m

s

440

s

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1

λ

=

0.773

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3 0
2 years ago
the inertial mass of an object is measured by exerting a force on the object and measuring the object's BLANK using an inertial
JulijaS [17]

Answer:

acceleration

sorry i answered late

3 0
3 years ago
After scientists analyze the results of their experiments they
Oksi-84 [34.3K]
They communicate their result to the scientific community- so to speak
8 0
3 years ago
Two equal forces are applied to a door. The first force is applied at the midpoint of the door, the second force is applied at t
Orlov [11]

Answer:

D) the second at the doorknob

Explanation:

The torque exerted by a force is given by:

\tau = Fdsin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the centre of rotation

\theta is the angle between the direction of the force and d

In this problem, we have:

- Two forces of equal magnitude F

- Both forces are perpendicular to the door, so \theta=90^{\circ}, sin \theta=1

- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force

--> therefore, the 2nd force exerts a greater torque

4 0
3 years ago
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