Answer:
Producers are autotrophs, or organisms that produce their own food. ... They are at the bottom of the food chain because they are eaten by other organisms, and they don't need to eat for energy. Producers make their own food through the process of photosynthesis instead of eating organic matter.
Answer:
Acid ammonium carbonate // Ammonium bicarbonate.
Explanation:
Hello, a 4 is missing in the fist H, thus:
The presence of the hydrogen between the ammonium and the carbonates characterizes the salt as an acid salt, so you could name it as acid ammonium carbonate or ammonium bicarbonate (similar to the sodium bicarbonate which is 
.
Best regards.
Answer:
The average of given values is 2.1221 ml
Explanation:
Given data:
Given measurements = 3.00 ml , 2.0 ml, 2.987 × 10⁻³ml , 3.4856 ml
Average value of given measurements = ?
Solution:
Formula:
Average value = sum of all measurement / total number of measurements
2.987 × 10⁻³ml = 0.002987 ml
Now we will put the values.
Average value = 3.00 ml + 2.0 ml + 0.002987 ml+ 3.4856 ml / 4
Average value = 8.488587 ml / 4
Average value = 2.1221 ml
The average of given values is 2.1221 ml
<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>
<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M r<span>(t)</span>=0.66</span> M/s
<span>0.2 M r<span>(t)</span>=1.32</span> M/s
<span>0.3 M r<span>(t)</span>=1.98</span> M/s
We can have the relationship:
<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2
Also, we assume m=1 which is the order of the reaction.
Thus, the relationship is simplified to,
r(t)/r0(t) = 2
r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>
0.66 <span>M/s=k×0.1 M</span>
<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>
Hey, lovely! It's a pretty lengthy process but here is a pretty clear video on how to do it. Hope this helps ya!
https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equat...
