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3 years ago

What two factors determine a molecule is polar or not

1 answer:

6 0

The two factors that determine whether or not a molecule is polar are if the individual bonds are even and the shape of the molecule. If the molecule is perfectly symmetric, the molecule will not be polar even if there are polar bonds present.

You might be interested in

Why is it so important in an ideal simple experiment to change only one variable from trial to trial?

RideAnS [48]

Because if you change two things then you do not know which one has affected or altered the dependent variable. if you only change one then you know what exactly changed and why

3 0

3 years ago

Oxygen and hydrogen are kept under the same temperature and pressure. Oxygen molecule is 16 times more massive than hydrogen one

lozanna [386]

Explanation:

When we increase the temperature of a substance then there will occur an increase in the kinetic energy of its molecules.

Also, K.E = $\frac{3}{2}kT$

So, kinetic energy is directly proportional to the temperature.

Hence, when temperature and pressure are kept the same for both oxygen and hydrogen gas then values of their kinetic energy will be the same irrespective of their masses.

Thus, we can conclude that kinetic energy of oxygen molecule is the same as compared to hydrogen molecule.

3 0

3 years ago

Calculate the density of CO2 at a pressure of 685.0 torr and 41.0°C . R=0.0821 (L*atm)/(mol *K)

Keith_Richards [23]

T=41+273=314 k

M=(12)+(16×2)=44g/mol

d=PM/RT

d=685×44/0.0821×314

d=1169.15 g/L

5 0

3 years ago

For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate

makvit [3.9K]

Answer: The standard electrode potential of the cell is 4.53 V.

Explanation:

We are given:

$E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=2.87-(-1.66)=4.53V$

Hence, the standard electrode potential of the cell is 4.53 V.

6 0

3 years ago

Zn +

saul85 [17]

Answer:

1. Theoretical yield = 2.03g

2. Actual yield 1.89g

Explanation:

Let us write a balanced equation. This is illustrated below:

Zn + 2HCI —> ZnCl2 + H2

Molar Mass of HCl = 1 +35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

1. From the equation,

73g of HCl produced 2g of H2.

Therefore, 74g of HCl will produce = (74 x 2)/73 = 2.03g

Therefore, theoretical yield = 2.03g

2. %yield = 93%

Theoretical yield = 2.03g

Actual yield =?

%yield = Actual yield /Theoretical yield x100

Actual yield = %yield x theoretical yield

Actual yield = 93% x 2.03 = (93/100)x2.03 = 1.89g

Actual yield =1.89g

4 0

4 years ago