Question

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Answer 1

What volume of 2.50 m lead ll nitrato

Answer 2

Answer:

For A: The volume of solution is 0.02 L

For B: The volume of concentrated $K_2Cr_2O_7$ solution is 5 mL

For C: The molarity of diluted NaOH is 0.4 M

Explanation:

• For A:

To calculate the volume for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of lead (II) nitrate solution = 2.50 M

Moles of lead ions = 0.0500 mol

Putting values in above equation, we get:

$2.50M=\frac{0.0500mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.0500mol}{2.50mol/L}=0.02L$

Hence, the volume of solution is 0.02 L

• For B:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$       ......(1)

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

$M_1=5.0M\\V_1=?mL\\M_2=0.01M\\V_2=250mL$

Putting values in equation 1, we get:

$5.0\times V_1=0.10\times 250\\\\V_1=5mL$

Hence, the volume of concentrated $K_2Cr_2O_7$ solution is 5 mL

• For C:

We are given:

$M_1=10.0M\\V_1=10.0mL\\M_2=?M\\V_2=250mL$

Putting values in equation 1, we get:

$10.0\times 10.0=M_2\times 250\\\\M_2=0.4M$

Hence, the molarity of diluted NaOH is 0.4 M