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Dmitry_Shevchenko [17]
2 years ago
7

(

Chemistry
2 answers:
Gnoma [55]2 years ago
7 0
What volume of 2.50 m lead ll nitrato
kogti [31]2 years ago
5 0

<u>Answer:</u>

<u>For A:</u> The volume of solution is 0.02 L

<u>For B:</u> The volume of concentrated K_2Cr_2O_7 solution is 5 mL

<u>For C:</u> The molarity of diluted NaOH is 0.4 M

<u>Explanation:</u>

  • <u>For A:</u>

To calculate the volume for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of lead (II) nitrate solution = 2.50 M

Moles of lead ions = 0.0500 mol

Putting values in above equation, we get:

2.50M=\frac{0.0500mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.0500mol}{2.50mol/L}=0.02L

Hence, the volume of solution is 0.02 L

  • <u>For B:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2       ......(1)

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated solution

M_2\text{ and }V_2 are the molarity and volume of diluted solution

We are given:

M_1=5.0M\\V_1=?mL\\M_2=0.01M\\V_2=250mL

Putting values in equation 1, we get:

5.0\times V_1=0.10\times 250\\\\V_1=5mL

Hence, the volume of concentrated K_2Cr_2O_7 solution is 5 mL

  • <u>For C:</u>

We are given:

M_1=10.0M\\V_1=10.0mL\\M_2=?M\\V_2=250mL

Putting values in equation 1, we get:

10.0\times 10.0=M_2\times 250\\\\M_2=0.4M

Hence, the molarity of diluted NaOH is 0.4 M

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A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ?C. The initial concentrations of Pb2+ and Cu2+ are
VARVARA [1.3K]

Answer:

a) Ecell = 0.5123 V

b) Ecell =  0.4695 V

c) [Pb2 +] = 4.75 M

Explanation:

a)

The reaction at the cathode is represented as follows:

Cu2 + + 2e- -> Cu (s) Eocathode = 0.34 V

The reaction at the anode is equal to:

Pb (s) -> Pb2 + + 2e- Eoanode = -0.13 V

The number of moles of the electrons that are involved is equal to n = 2

Standard cell potential equals Eo = Eocathode - Eoanode = 0.34 V- (-0.13 V) = 0.47 V

 The initial cell potential can be calculated with the following formula:

Ecell = Eocell - - 0.0592 / n) log ([(Pb2 +)] / [(Cu2 +)]) = 0.47 - (0.0592 / 2) log (0.052 / 1.4) = 0.5123 V

b)

The reaction in the cell is equal to:

Cu2 + + Pb (s) -> Cu (s) + Pb2 +

The concentration of Cu2 that gives the exercise is equal 0.2 M

Therefore, the change in concentration for Cu2 + is equal to:

Cu2 + = 1.4 M - 0.2 M = 1.2 M

We use the formula from part a)

Ecell = Eocell - (0.0592 / n) log ([(Pb2 +)] / [(Cu2 +)]) = 0.47 - (0.0592 / 2) log (1,252 / 1.2) = 0.4695 V

c)

To find the concentration of Pb2 + when there is a potential change in the cell of 0.37 V, we must clear the concentration of Pb2 + from the following formula:

Eccell = Echocell - (0.0592 / n) log (([Pb2 +]) / ([Cu2 +]))

0.0296 log ([Pb2 +] / [Cu2 +]) = (Eocélula - Ecélula / 0.0296)

Clearing Pb2 +:

[Pb2 +] = 4.75 M

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how does an airplane’s kinetic energy and potential energy change as it takes off and lands? How does this energy change relate
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Answer: As the airplane goes higher, the mechanical energy is changed into gravitational potential energy. While flying, some energy is lost through drag to thermal (heat) energy and sound energy. Some is also lost as the plane makes the air around it move. ... As speed and height decrease, kinetic and potential energy decrease.

Explanation:

Hope this help

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What is an air mass? Where on Earth might you find a hot and dry air mass?
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The wave mechanical model of the atom is required to explain the
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The wave-mechanical model of the atom is required to explain the spectra of elements with multi electron atoms.

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Wave mechanical theory say that every electron surrounding a nucleus occupies a certain orbit and moves in a certain direction, but the orbit is like a wave of energy or cloud but not a ring. It was proposed in the 1920s, when scientists Erwin Schrodinger and Louis Victor de Broglie concluded that the Bohr’s model is not suitable for electron location determination.

Based on many assumptions, scientists began to guess as accurately as possible about the behaviour of electrons at different energy levels around the nucleus. Because all electrons are negatively charged, they tend to push their elbows when they are too close together, moving away and changing direction. Each plane has one or more orbits that have more than one electrons that move around the nucleus in a specific patterns or shape.

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