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anzhelika [568]
2 years ago
5

Hi May I know what is the answer and how to get it

Chemistry
1 answer:
Trava [24]2 years ago
8 0

Answer:

D

Explanation:

When lead ions and sulfate ions bond, they form sediment so neither a nor b can be the answer.

The important thing is that two nitrate ions were originally bonded with one lead ion, while two potassium ions bonded with a sulfate ion.

Finally, since potassium and nitrate ions don't form sediment these two ions must remain. Therefore the answer is D

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if carbon which has an electrongavity of 2.5 bonds with hydrogen, which has an electrongavity of 2.1, the bond between the two a
sukhopar [10]

Answer:

If carbon which has an electrongavity of 2.5 bonds with hydrogen, which has an electrongavity of 2.1, the bond between the two atoms will be classified as a(n) covalent bond → Totally TRUE

Explanation:

We must follow the Pauling's rules to solve these question.

The electonegativity of an element is defined as the ability it has to attract electrons that link it to another element. It is a periodic property, which allows predicting the polarity of the bond formed between two atoms, as well as its covalent or ionic character.

The Pauling scale values ​​range from 0.7 for Francium (the least electronegative element) to 4 for Fluorine, the most electronegative. Using the electronegativities table we can predict the polarity of some compounds

ΔEn (C-H) = 2.5 - 2.1 = 0.4 → This is a covalent bond.

ΔEn ≤ 0.4 → Covalent non polar bond

0.5 < ΔEn < 1.7 → Covalent polar bond

ΔEn ≥ 1.7 → Ionic bond

8 0
3 years ago
Pls<br> Due today pls help asfast as possible
Stels [109]

Answer: D. 10,000 km = Exosphere; 690 km = Thermosphere; 85 km Mesosphere; 50 km = Stratosphere; 20 km = Troposphere

2. True

3. True

4. True

5. True

5 0
2 years ago
Use the periodic table to help you.
BARSIC [14]
The answer would be Sb
Because N P and O are all non metals whereas Sb is a metal
7 0
4 years ago
Read 2 more answers
The melting points for the compounds li2s, rb2s, and k2s are 900°c, 530°c, and 840°c, respectively. list these three compounds i
Mila [183]

Answer: The order of increasing lattice energy is Li_2S>K_2S>Rb_2S

Explanation: Lattice energy is defined as the energy required to break the intermolecular force that is responsible for the formation of a lattice.

Melting point is defined as the temperature at which solid gets converted into liquid due to the weakening of the bonds in the solid form.

  • Relation between lattice energy and Melting point:

The relationship between these two is direct.

\text{Lattice energy}\propto \text{Melting point}

More the melting point of a compound, more will be its lattice energy.

Order of increasing Lattice energy will be:

Li_2S>K_2S>Rb_2S

7 0
3 years ago
Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the
Nataliya [291]

Answer: The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

Explanation:

Given: Concentration of hydrogen fluoride = 0.126 M

Concentration of fluoride ions = 0.1 M

Volume of HCl = 9.0 mL

Concentration of HCl = 0.01 M

Volume of HCl = 25.0 mL

Moles of F^{-} ions are calculated as follows.

Moles of F^{-} = molarity \times volume\\= 0.1 M \times 0.025 L\\= 0.0025 mol

Moles of HF are as follows.

Moles of HF = Molarity \times Volume\\= 0.126 M \times 0.025 L\\= 0.00315 mol

Moles of HCl are as follows.

Moles of HCl = Molarity \times volume\\= 0.01 M \times 0.009 L\\= 0.00009 mol

Now, reaction equation with initial and final moles will be as follows.

                        H^{+}  + F^{-}  \rightarrow  HF

Initial:      0.00009  0.0025    0.00315

Equilibrium:      (0.0025 - 0.00009)    (0.00315 + 0.00009)

                                = 0.00241                    = 0.00324

Total volume = (9.00 mL + 25.0 mL) = 34.0 mL = 0.034 L

Hence, concentration of fluoride ions is calculated as follows.

Concentration = \frac{moles}{volume}\\= \frac{0.00241 mol}{0.034 L}\\= 0.0709 M

Thus, we can conclude that concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.

7 0
3 years ago
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