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lana66690 [7]
3 years ago
9

If your front lawn is 15.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1150 new snow flakes every min

ute, how much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 2.20 mg.
Chemistry
1 answer:
svlad2 [7]3 years ago
4 0
First, we calculate the total are:
Area = 15 x 20
Area = 300 sq ft

Snowflakes accumulated per minute = 1150 x 300
Snowflakes per minute = 345,000 snowflakes per minute

Snowflakes per hour = 345,000 x 60
Snowflakes per hour = 20,700,000
Snowflakes per hour = 20.7 x 10⁶

Mass of one snowflake = 2.2 mg
Mass of one snowflake = 2.2 x 10⁻³ g
Mass of one snowflake = 2.2 x 10⁻⁶ kg

Mass of snow = 20.7 x 10⁶ x 2.2 x 10⁻⁶
Mass of snow = 45.54 kg per hour
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Elements belonging to the same period have the same electron shell, the same number of orbits filled with electrons.
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At a certain temperature the vapor pressure of pure acetic acid HCH3CO2 is measured to be 226.torr. Suppose a solution is prepar
Rudiy27

Answer:

The partial pressure of acetic acid is 73.5 torr

Explanation:

Step 1: Data given

Total pressure is 226 torr

mass of acetic acid = 126 grams

mass of methanol = 141 grams

 

Step 2: Calculate moles of acetic acid

moles acetic acid = mass acetic acid / molar mass acetic acid

moles acetic acid = 127 grams / 60.05 g/mol

moles acetic acid = 2.115 moles

Step 3: Calculate moles of methanol

moles methanol = 141 grams / 32.04 g/mol

moles methanol = 4.40 moles

Step 4: Calculate total moles

Total moles = moles of acetic acid + moles methanol

Total moles = 2.115 moles + 4.40 moles

Total moles = 6.515 moles

Step 5: Calculate mole fraction of acetic acid

2.115 moles / 6.515 moles = 0.325

Step 6: Calculate partial pressure of acetic acid

P(acetic acid) = 0.325 * 226

P(acetic acid) = 73.45 torr ≈73.5

 

We can control this by calculating the partial pressure of methanol

mole fraction of methanol = (6.515-2.115)/6.515 = 0.675

P(methanol) = 0.675 * 226 = 152.55

226 - 152.55 = 73.45 torr  

The partial pressure of acetic acid is 73.5 torr

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3 years ago
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