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wlad13 [49]
3 years ago
11

What volume will 35.9 g of hydrogen gas (H2) occupy at STP?

Chemistry
2 answers:
Nataly [62]3 years ago
8 0
35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L
notka56 [123]3 years ago
6 0

Answer: 402.08 L

Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{35.9 g}{2g/mol}=17.95moles

Now 1 mole of H_2 molecule occupy= 22.4 L at STP

17.95 moles of H_2 molecule contains = \frac{22.4}{1}\times 17.95=402.08 L at STP

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