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4 years ago

Convert the following reaction into its formula equation and complete the product.

Chemistry

1 answer:

Blababa [14]4 years ago

6 0

Answer:

Fe( NO3)2 + Na2S => FeS + 2 NaNO3

Explanation: Iron(II) nitrate Fe(NO3)2 reacts with sodium sulfide( Na2S) will produce Iron sulfide( FeS )and 2 moles of sodium nitrate ( NaNO3).

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What is the percent by mass of oxygen in sulfur dioxide?

Kitty [74]

(32/64)=0.5 *100= 50%

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3 years ago

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in one analysiss 1.09 x 10^13 molecules of ozone were found in 1.00ml of air how many ozone moles are these

Step2247 [10]

Answer:10,900,000,000,000 ozone moles

Explanation:

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3 years ago

Pls help tysm <3 :D:D

Marianna [84]

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3 years ago

Define a salt bridge. Define a salt bridge. A pathway between the cathode and anode in which ions are oxidized. A pathway, compo

ycow [4]

Answer:

A pathway by which counter ions can flow between the half-cells without the solutions in the half-cell totally mixing.

Explanation:

Salt bridge is a link between oxidation half and reduction half of a galvanic cell.

Functions of salt bridge are:

Maintaining electrical neutrality

Preventing cell from reaching equilibrium

For creating salt bridge, a U shaped glass tube is filled with an inert electrolyte. Electrolytes used in the salt bridge generally do not reacts with the cell chemicals.

Cations and anions of the electrolytes have same ionic conductivity and hence, migrate with the same speed.

Most commonly potassium chloride, sodium chloride and potassium nitrate are used as an electrolyte in salt bridge.

Electrolyte are generally mixed with agar agar to prevent mixing of chemicals in the two half cells.

5 0

3 years ago

Which of the following would have the largest second ionization energy? Osr o Zr ΟΥ 0 Rb

Art [367]

Answer:

Explanation:

Second ionization energy is the energy required for the removal of the second loosely bonded valence electron from an isolated gaseous atom.

The given elements:

Rb , Sr, Y and Zr

These are the elements of the fifth period.

The electronic configuration of Rb - $[Kr]5s^1$

The electronic configuration of Sr - $[Kr]5s^2$

The electronic configuration of Y - $[Kr]5s^24d^1$

The electronic configuration of Zr - $[Kr]5s^24d^2$

<u>When one electron is removed from Rb, the cation attains the noble gas configuration due to which the removal of second electron from Rb is very very difficult. Thus, Rb has the largest second ionization energy.</u>

The values of the second ionization of these elements are:

Rb = 2633 kJ/mol

Sr = 1064.2 kJ/mol

Y = 1180 kJ/mol

Zr = 1270 kJ/mol

4 0

3 years ago