How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all o
1 answer:
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<u>Answer:</u> The amount of energy released per gram of is -71.92 kJ
<u>Explanation:</u>
For the given chemical reaction:
The equation used to calculate enthalpy change is of a reaction is:
The equation for the enthalpy change of the above reaction is:
Taking the standard enthalpy of formation:
Putting values in above equation, we get:
We know that:
Molar mass of pentaborane -9 = 63.12 g/mol
By Stoichiometry of the reaction:
If 2 moles of produces -9078.57 kJ of energy.
Or,
If of
produces -9078.57 kJ of energy
Then, 1 gram of will produce =
of energy.
Hence, the amount of energy released per gram of is -71.92 kJ