You need to ask your teacher for any help and to evaluate and double check each step.
Answer:
The answer is the last one (32x^7y^15)
You can bring x to the second power (x^2) because (x) is basically x^1. This is a basic exponent rule. (x^m)^n = x^m times n.
Then you can apply this rule to (2xy^3)^5. First you bring two to the fifth power and get 32. Then you bring x^5 according to the rule. Then you bring y^15, also because of the rule.
Now you have:
x^2 times 32x^5y^15
Now you just multiply the like terms together (x^2 and x^5)
When you multiply two exponents with the same base, you add the exponents together: a^n times a^m = a^n+m.
So you end up with 32x^7y^15
Given:
and 
where 
.
To find:
The explicit formula for the given recursive formula.
Solution:
We know that recursive formula of an AP is:
Where, d is the common difference.
We have,
Here, d=9.
The first term of the AP is .
The explicit formula for an AP is:
Substituting and 
, we get
Therefore, the required explicit formula for the given sequence is .
Answer:
f = 3 1/2
Step-by-step explanation:
f = 2t - 3f Substitute 7 for t
f = 2(7) - 3f Multiply
f = 14 - 3f
+3f + 3f Add 3f to both sides
4f = 14 Divide both sides by 4
f = 3 1/2
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